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3 years ago

15

A very long wire carries a uniform linear charge density of 5 nC/m. What is the electric field strength 13 m from the center of

the wire at a point on the wire's perpendicular bisector? (ε 0 = 8.85 × 10-12 C2/N · m2)

1 answer:

kipiarov [429]3 years ago

5 0

Answer:

E=6.91 N/C

Explanation:

Given that

Linear Charge density ,λ = 5 nC/m

Distance ,R= 13 m

We know that formula for long wire to find electric field

$E=\dfrac{\lambda }{2\pi \varepsilon _0R}$

E=Electric field

R=Distance

εo=8.85 x 10⁻¹² C²/N.m²

λ=Linear Charge density

Now by putting the values

$E=\dfrac{5\times 10^{-9}}{{2\times \pi \times 8.85\times 10^{-12}\times 13}}$

E=6.91 N/C

Therefore the electric filed at distance 13 m will be 6.91 N/C

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