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3 years ago

Explain what an induced current is.please help me with at least 2 sentences.

Chemistry

2 answers:

Vesna [10]3 years ago

7 0

Explanation:

If a coil of wire is placed in a changing magnetic field, a current will be induced in the wire. This current flows because something is producing an electric field that forces the charges around the wire.

Deffense [45]3 years ago

6 0

An induced current is a conducting loop that is exposed to a changing magnetic field. And it is knows as induced current

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Write a balanced equation for the double-replacement neutralization reaction described, using the smallest possible integer coef

g100num [7]

<u>Answer:</u> The balanced chemical equation is given below.

<u>Explanation:</u>

Double-displacement reaction is defined as the reaction in which exchange of ions takes place. The general equation representing this reaction follows:

$AB+CD\rightarrow CB+AD$

The balanced chemical equation for the reaction of barium hydroxide and perchloric acid follows:

$Ba(OH)_2(aq.)+2HClO_4(aq.)\rightarrow Ba(ClO_4)_2(aq.)+2H_2O(l)$

By Stoichiometry of the reaction:

1 mole of barium hydroxide reacts with 2 moles of perchloric acid to produce 1 mole of barium chlorate and 2 moles of water molecule.

Hence, the balanced chemical equation is given above.

8 0

3 years ago

Consider the following reaction:

zzz [600]

Answer:

Question 1: <u>Both the rate of reaction of H₂O₂ and the rate of formation of H₂O are:</u>

$6.6\cdot 10^{-3}mol/(liter.s)$

Question 2: <u>0.60 moles of O₂ are formed in the first 50 s of reaction.</u>

<u />

Explanation:

The coefficients of the balanced chemical equation tells the relation of formation of the reactants into the products, which is also the relation between their rates of reaction.

The balanced chemical equation (given) is:

$2H_2O_2(aq)\rightarrow 2H_2O(l)+O_2(g)$

Then, in the same time that 2 moles of H₂O₂ react, 2 moles of H₂O and 1 mol of O₂ are formed.

<u>1. Question 1.</u>

That means that the rate of formation of O₂ is half the rate of reaction of H₂O₂ and half the rate of formation of H₂O.

Hence, if the instantaneous rate of formation of O₂ is 3.3×10⁻³moles/(liters×seconds), then the rate of reaction of H₂O₂ and the rate of formation of H₂O is twice:

$2\times 3.3\cdot 10^{-3}mol/(liter.s)=6.6\cdot 10^{-3}mol/(liter.s)$

<u>2. Question 2.</u>

<u></u>

First you must find how much the concentration has changed.

You can read the initial concentration of H₂O₂ on the graph. It is the y-intercept. It is 1.0M.

You can read the approixmate concentration of H₂O₂ at the time 50 s. It is about 0.2M.

Then the change in concentration in the first 50 s of reaction is about 1.0M - 0.2M = 0.8M.

Now you can convert the concentration 0.8M into number of moles, using the volume (1.5 liters), assuming the liquid volume does not change, and the molarity definition (molarity is the number of moles of solute in one liter of solution)

$\Delta [H_2O_2]=\Delta moles/Volume(liters)$

$0.8M=\Delta moles/1.5liter\\\\\Delta moles=0.8M\times 1.5liter=1.2mol$

Hence, 1.2 mol of H₂O₂ have reacted in the first 50s of reaction.

From the coefficients of the chemical equation, the number of moles of O₂ formed is half the number of moles of H₂O₂ that react.

Thus, 1.2mol/2 = 0.60 moles of O₂ are formed in the first 50 s of reaction.

7 0

3 years ago

Which equation correctly defines Hooke's law?

zhuklara [117]

The equation of hooke's law is F=KX

7 0

3 years ago

Read 2 more answers

18.2L of gas at 95°C and 760 torr is placed in a 15L container at 80 degrees * C ; what is the new pressure ?

romanna [79]

Answer:

884.56 torr

Explanation:

Formula: $\frac{P_{1}V_{1} }{T_{1}} = \frac{P_{2}V_{2} }{T_{2}}$

P = Pressure

V = Volume

T = Temperature in kelvin (Celsius + 273.15)

$\frac{(760)(18.2) }{368.15} = \frac{P(15) }{353.15}$

$P = \frac{(760)(18.2)(353.15) }{(368.15)(15)}$

P = 884.56169

4 0

3 years ago

Can someone help me with my chemistry homework please???

taurus [48]

<h2><u>Answers:</u></h2>

<u>1.) Lithium and Sulfide: </u>

Formula: $\bold{Li_{2}S}$

Ion Charges: $\bold{Li~1+,~Li~1+,~S~2-}$

<h3 />

<u>2.) Lithium and Chlorine:</u>

Formula: $\bold{2LiCl}$

Ion Charges: $\bold{Li~1+, Li~1+,Cl~1-,Cl~1-}$

<h3 />

<u>3.) Lithium and Oxygen: </u>

Formula: $\bold{Li_{2}O}$

Ion Charges: $\bold{Li~1+,Li~1+,O~2-}$

<u>4.) Lithium and Nitrogen:</u>

Formula: $\bold{Li_{3}N}$

Ion Charges: $\bold{Li~1+,Li~1+,Li~1+,N~3-}$

<u>5.) Magnesium and Sulfur:</u>

Formula: $\bold{MgS}$

Ion Charges: $\bold{Mg~2+,S~2-}$

<u>6.) Magnesium and Chlorine:</u>

Formula: $\bold{MgCl_2}$

Ion Charges: $\bold{Mg~2+,Cl~1-,Cl~1-}$

<u>7.) Magnesium and Oxygen:</u>

Formula: $\bold{MgO}$

Ion Charges: $\bold{Mg~2+,O~2-}$

<u>8.) Magnesium and Nitrogen: </u>

Formula: $\bold{Mg_3N_2}$

Ion Charges: $\bold{Mg~2+,Mg~2+,Mg~2+,N~3-,N~3-}$

<h2 /><h2><u>Explanation:</u></h2>

______________________________

<h3><u>Lithium and Sulfur: </u></h3>

In order to make Lithium Sulfide, There must be 2 Lithium and 1 Sulfur. You transfer the electrons from both Lithium's to the Sulfur.

<h3 /><h3><u>Lithium and Chlorine:</u></h3>

In order to make Lithium Chloride, There must be 2 Lithium and 2 Chlorine. You transfer the electrons from both Lithium's to the Chlorines, (One electron for each chlorine.)

<h3 /><h3><u>Lithium and Oxygen:</u></h3>

In order to make Lithium Oxide, There must be 2 Lithium and 1 Oxygen. You transfer the electrons from both Lithium to Oxygen.

<h3 /><h3><u>Lithium and Nitrogen:</u></h3>

In order to make Lithium Nitride, There must be 3 Lithium and 1 Nitrogen. You transfer the electrons from all 3 Lithium to Nitrogen.

<h3 /><h3><u>Magnesium and Sulfur:</u></h3>

In order to make Magnesium Sulfide, There must be 1 Magnesium and 1 Sulfur. You transfer the both electrons from Magnesium to Sulfur.

<h3 /><h3><u>Magnesium and Chlorine:</u></h3>

In order to make Magnesium Chloride, There must be 1 Magnesium and 2 Chlorine. You transfer on electron to each Chlorine.

<h3 /><h3><u>Magnesium and Oxygen:</u></h3>

In order to make Magnesium Oxide, There must be 1 Magnesium and 1 Oxygen. You transfer both electrons from Magnesium to Oxygen.

<h3 /><h3><u>Magnesium and Nitrogen:</u></h3>

In order to make Magnesium Nitride, There must be 3 Magnesium and 2 Nitrogen. You transfer 3 electrons from Magnesium to Nitrogen.

<h3 />

______________________________

4 0

3 years ago