If the distance to a point source of sound is doubled, by a multiplicative factor of 4, the intensity changes.
Intensity of sound is the sound which is perpendicular to sound wave propogation per unit area. It is dependent on the Surface of source sound.
Intensity is the Power per unit area. Its SI unit is Watt/m².
As we move away from a source of sound, the sound starts to diminish. This is due to the decreasing sound intensity with distance.
It can also be understood by the fact that on increasing distance, the Power radiated by the source spreads over a larger area. Hence, the Intensity decreases gradually.
Since, Intensity is proportional to the square of the distance.
Hence, on doubling the distance, Intensity reduces to one fourth of the initial intensity or reduces by a multiplicative factor of 4.
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Answer:
In odd nuclei, the left out proton or neutron will contribute to the spin of the nucleus.
Explanation:
The meaning of odd nuclei is atomic mass is odd.
A=odd number.
A=Z+n
Here, Z is proton either it will odd or n will odd which is neutron.
Now according to the shell model the left out proton or neutron will contribute to the spin and parity.
For example,
Take the case of isotope of nitrogen-15.
Here Z is 7, and n is 8 will not contribute in spin.
Now, for Z=7.

Here,

and, L=1.
Fort parity,

Put the value of L.
Parity will be -1.
Now, spin will be
.
Answer:
P = 1.45 hp or 1.94kW
Explanation:
Given:
v = 2.5m/s
uk = 0.06
m = 60kg
Fk = uk*m*g*fsin(15)
Fk = 0.06*85*9.81*60*sin(15)
Fk = 776.15 N
Power=force*speed
P = F*v
P = 776.15N*2.5m/s
P = 1940.36 W
1 Horsepower = 0.7457 Kilowatts
P = 1.45 hp
Given the particle's acceleration is

with initial velocity

and starting at the origin, so that

you can compute the velocity and position functions by applying the fundamental theorem of calculus:


We have
• velocity at time <em>t</em> :

• position at time <em>t</em> :
