Explanation:
Given data
Inductance L=12*10^-³H
Capacitance C= 3.5*10^-6F
Resistance R= 3.3 Ohms
Voltage V=115v
Capacitive reactance Xc=?
inductive reactance Xl=?
Impedance Z=?
Phase angle =?
A. Resonance frequency
In RLC circuit resonance occurs when capacitive reactance equals inductive reactance
f=1/2pi √ LC
f=1/2*3.142 √ 12*10^-³*3.5*10^-6
f=1/6.284*0.0002
f=1/0.00125
f=800HZ
B. Find Irms at resonance.
Irms=R/V
Irms=3.3/115
Irms=0.028amp
Find the capacitive reactance XC in Ohms
Xc=1/2pi*f*C
Xc=1/2*3.142*800*3.5*10^-6
Xc=1/0.0176
Xc=56.8 ohms
To find the inductive reactance
Xl=2pifL
Xl=2*3.142*800*12*10^-3
Xl=60.3ohms
d) Find the impedance Z.
Z=√R²+(Xl-Xc)²
Z=√3.3²+(60.3-56.8)²
Z=√10.89+12.25
Z=√23.14
Z=4.8ohms
Phase angle =
Tan phi=Xc/R=56.8/3.3
Tan phi=17.2
Phi=tan-1 17.2
Phi= 1.51°
Air spaces are used in insulation because air is a poor conductor.
Answer:
<u>Very low</u>
<u>Explanation:</u>
It is fair to say to a reasonable extent that there are very low chances that radio transmissions from Earth or messages sent on distant space probes will ever be received by living beings
.
Bear in mind that for years some scientists have believed without any substantial evidence that there are other living beings in distant space.
centrifugal force is a fictitious force. What is happening is that since the earth itself is not a rigid body it will deform when under motion. Although gravity attempts to make the earth spherical, as it is rotating the earth deforms, in such away that it flattens to become an oblique spheroid. This happens as the material at the equator must have a net resultant centripetal force (not centrifugal) which causes its position of equilibrium from the center of the earth to be further away than at the poles as they do not have this force as they are not rotating around the center of mass.
The diameter of the wire is 2.8 * 10^-3 m.
<h3>What is the length?</h3>
Mass of the wire = 1.0 g or 1 * 10^-3 Kg
Resistance = 0.5 ohm
Resistivity of copper = 1.7 * 10^-8 ohm meter
Density of copper = 8.92 * 10^3 Kg/m^3
V = m/d
But v = Al
Al = m/d
A = m/ld
Resistance = ρl/A
= ρl/m/ld =
l^2 = Rm/ρd
l = √ Rm/ρd
l = √0.5 * 1 * 10^-3 / 1.7 * 10^-8 * 8.92 * 10^3
l = 1.82 m
A = πr^2
Also;
A = m/ld
A = 1 * 10^-3 Kg / 1.82 m * 8.92 * 10^3 Kg/m^3
A = 6.2 * 10^-5 m^2
r^2 = A/ π
r = √A/ π
r = √6.2 * 10^-5 m^2/3.142
r = 1.4 * 10^-3 m
Diameter = 2r = 2( 1.4 * 10^-3 m) = 2.8 * 10^-3 m
Learn more about resistivity:brainly.com/question/14547003
#SPJ4
Missing parts;
Suppose you wish to fabricate a uniform wire from 1.00g of copper. If the wire is to have a resistance of R=0.500Ω and all the copper is to be used, what must be (a) the length and (b) the diameter of this wire?
