Because CH4 is the limiting reagent, we must find how many moles we have.
1. 5.14 g CH4 * (1 mol CH4 / 16.04 g/mol) = .32125 moles CH4
Now we know that there are .32125 moles of CCl4 produced as well.
Next, take .32125 moles and multiply it by the atomic mass of CCl4, which is 153.82 grams = 49.29 g CCl4 produced by the reaction.
I think the answer will C
Answer:
The deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer because Organic compounds that are neither acids or bases do not react with either NaOH or HCl and, therefore remain more soluble in the organic solvent and are not extracted.
Explanation:
That formula would be HNO2
