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dexar [7]
3 years ago
11

How much work is done by a 450.0 Wengine in 15.0 s?

Physics
1 answer:
finlep [7]3 years ago
5 0

Answer:

6700j

Explanation:

WD=force×distance

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A woman drives a golf ball off the tee to a speed of 28 m/s. The mass of the ball is 45 g and tIf the angle of the flight was in
Novay_Z [31]

Answer:

456

Explanation:

impulse = Force x (time of contact)

this isn't really much information but hope this helps !: )

8 0
3 years ago
A car drives to the east in a time of 6 hours. Then, immediately (not realistic, but just assume this is the case for this probl
garri49 [273]

Answer:

Average speed of car in the first trip is 10 km/hr    

Explanation:

It is given that first the car drives 6 hours to the east

Then travels 12 km to west in 3 hours

Average speed for the entire trip = 8 km/hr

Total time = 3+6 = 9 hour

So distance traveled in 9 hour = 9×8 = 72 km

As the car travel 12 km in west so distance traveled in east = 72-12 = 60 km

Time by which car traveled in east = 6 hour

So speed =\frac{distance}{time}=\frac{60}{6}=10km/hr

So average speed of car in the first trip is 10 km/hr

7 0
3 years ago
HELP PLEASE!
seraphim [82]

Answer:

ᵒᵒᵒᵒᵏᵏ

ᵏᵏᵏ

Explanation:

ᵒᵒᵏᵏᵏᵏᵏᵏᵏᵏᵏᵏᵏᵏ

ᵏᵒᵒᵒᵏᵏᵏᵏᵏᵏᵏᵏᵏᵏᵏᵏᵏᵐᵐ

6 0
3 years ago
A conducting coil of 1470 turns is connected to a galvanometer, and the total resistance of the circuit is 56.0 . The area of ea
Damm [24]

Answer:

 B = - 1.51 10⁻⁷ T

Explanation:

For this exercise we can use Faraday's law of induction

          E = - - \frac{d \phi _B}{dt} = - \frac{d (B A cos \theta )}{dt}

           

In this case, they indicate that the normal and the magnetite field are in the same direction, so the angle is zero (cos 0 = 1), they give the area of ​​the loop A = 4.32 10⁻⁴ m² and since we have N = 1470 turns in each one a voltage is induced

          E = - N B A

          B = -E A / N               (1)

we find the induced voltage with ohm's law

         V = i R

where the current is defined by

         i = Q / t

we substitute

          V = Q R / t

 

let's calculate

         V = 9.18 10-3 56.0 / t

We must assume a time normally is t = 1 s

         V = 0.514 V

this is the voltage in the circuit which must be the induced voltage V = E

we substitute in 1

         B = - 0.514 4.32 10⁻⁴ / 1470

         B = - 1.51 10⁻⁷ T

3 0
3 years ago
Define the focus of a concave lens ​
Sophie [7]

Answer:

<u>Principal</u><u> </u><u>focus</u><u> </u><u>of</u><u> </u><u>concav</u><u>e</u><u> </u><u>lens</u><u> </u><u>-</u><u> </u>

★ The point at which rays parallel to principal axis coming from infinity appear to converge after being refracted from concave lens is called the principal focus of concave lens.

<em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em>

• <u>Additional</u><u> information</u><u> </u><u>-</u><u> </u>

★ Principal focus - A number of rays parallel to the principal axis after reflection from a concave mirror meet at a point on the principal axis or appear to come from a point after reflection from a convex mirror on the principal axis. This is called principal focus.

8 0
3 years ago
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