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Deffense [45]
3 years ago
5

The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is __________V when

the concentration of Zn2+ = 1.0 M and the
concentration of Pb2+ = 2.0 x 10-4 M.



Pb2+(aq) + Zn(s) ---> Zn2+(aq) + Pb(s)
Physics
1 answer:
ankoles [38]3 years ago
8 0

Answer:

0.52 V

Explanation:

From Nernst equation;

Ecell =E°cell - 0.0592/n log Q

E°cell = +0.63 V

[Zn2+] =1.0 M

[Pb2+] = 2.0 x 10-4 M

n = 2

Ecell = 0.63 - 0.0592/2 log[1.0/2.0 x 10-4]

Ecell = 0.63 - 0.11

Ecell = 0.52 V

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A musician in a group plays a wrong note. would this note disrupt the harmony of the rhythm of the song being played? explain yo
Eddi Din [679]
If a musician plays a wrong note, he will disrupt the harmony of rhythm of the song. This is because, he will be able to produce a sound of different wavelength which will cause a possible destructive interference with the waves being produced by his groupmates. 
8 0
3 years ago
A gun fires a bullet vertically into a 1.40-kg block of wood at rest on a thin horizontal sheet. If the bullet has a mass of 22.
Bogdan [553]

Answer:

A. 1.172 metres

B. 6.82 Ns

C. 4.796 m/s

Explanation:

The total initial momentum is gotten by multiplying the mass and initial velocity of the both bodies.

The 1.40 kg block is at rest so velocity is zero and has no momentum.

The bullet of mass 22 g = 0.022 kg with velocity of 310 m/s

Momentum = 310*0.022

Momentum = 6.82 Ns.

If the bullet gets embedded they will both have common velocity v

6.82 = (0.022+1.40)v

6.82 = 1.422v

V = 6.82/1.422

V = 4.796 m/s

How high the block will rise after the bullet is embedded is given by

H = (U²Sin²tita)/2g

Where tita is 90°

H = (4.796² * sin²(90))/(2*9.81)

H =( 23.001616*1)/19.62

H = 1.172 metres

6 0
4 years ago
A Volt/Amp Is Also Known As.?
maxonik [38]

A volt/amp is also know as a volt ampere

4 0
4 years ago
Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the volume flow rate of the fluid in m^3/
fenix001 [56]

Answer:

Volume flow rate = 1.41 \times 10^{-3}m^3/s

Explanation:

The volume flow rate through a channel can be gotten by multiplying its area and its velocity.

The channel under consideration is a circular channel. Hence, the cross-sectional area can be calculated by using the relation for calculating the area of a circle

Cross-sectional area = \pi \times d^{2}/4

A = \pi \times (3\times 10^-2)^2  /4 = 7.07 \times 10 ^-4 m^2

volume flow rate= A =  7.07 \times 10 ^-4 m^2 X 2.0 = 1.41 \times 10^{-3}m^3/s

Volume flow rate = 1.41 \times 10^{-3}m^3/s

7 0
4 years ago
9. A statue is to be scaled down isomorphically (It will have its size changed without changing its shape). It starts with an in
Fynjy0 [20]

Answer:

   m = 1.45 kg

Explanation:

For this exercise we look for size reduction in height

              Reduction = y / y₀

              Reduction = 2.15 / 6.75

              Reduction = 0.3185

As the statue should not be deformed, all reduction has the same factor.

Let's use the concept of density

       ρ = m / V

Initial statue

         ρ = m₀ / V₀

         

It is reduced

         V = x y z

         V = 0.3185 x₀ 0.3185 y₀ 0.3185 z₀

         V = 0.3185³ V₀

       

Density is

         ρ = m / V

         ρ = m / 0.3185³ V₀

As the density remains constant we can match them

         m₀ / Vo = m / 0.3185³ V₀

         m = 0.3185³ m₀

Let's calculate

        m = 0.3185³ 45

        m = 0.03231   45

        m = 1.45 kg

5 0
3 years ago
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