Answer:
1. use a ruler to measure how many heights the ball falls down.
2. use notes to record observations.
Answer:
3.51 g of oxygen per gram of gasoline is required.
Explanation:
Solution:
First of all we will write the balance chemical equation.
C8H18 + 12.5O2 → 8CO2 + 9H2O
This equation shows that,
1 mole of gasoline react with 12.5 mole of oxygen for complete burning.
mass of one mole of gasoline = 8×12 + 18×1 = 114 g
mass of 12.5 mole of oxygen = 12.5 (16×2) = 400 g
Formula:
mass of oxygen per gram of gasoline = (400 / 114) = 3.51
so, 3.51 g of oxygen require for per gram of gasoline.
Answer:
A. The amount of energy needed to remove 1 mole of electrons from 1 mole of ground-state atoms or ions in the gas phase.
Explanation:
Ionization energy is the quantity of energy required to remove an electron in ground electronic state from an isolated gaseous atom or ion, resulting in a cation. kJ/mol is the expresion we use for this energy, it refers to the amount of energy it takes for all the atoms in a mole to lose one electron each.
Ionization energy can be used as an indicator of reactivity and can be used to help predict the strength of chemical bonds because the more electrons are lost, the more positive the ion will be and the harder it will be to separate the electrons from the atom.
I hope you find this information useful and interesting! Good luck!
