Answer:
B. Reduction occurs at the cathode.
Step-by-step explanation:
That's the <em>definition</em>: The cathode is the electrode at which reduction occurs.
A is <em>wrong</em>. The cathode gains electrons through the external circuit.
C is <em>wrong</em>. The cathode has the electrons, so cations move toward it.
D is <em>wrong</em>. Reduction occurs at the cathode, so the oxidation number decreases.
Answer:
C2H5NO2
Explanation:
Glycine | C2H5NO2 - PubChem.
weight of glycine= 75.07 g/mol
Answer:
community according to me
That is the balanced chemical equation.
Before reaction,
milli-moles of Mg(OH)2 = 100 x 0.02 = 2
milli-moles of HNO3 = 100 x 0.05 = 5
After reaction:
Mg(OH)2 is limiting reagent. It will react completely leaving some HNO3 behind.
milli-moles of HNO3 react = 2 x coefficient of HNO3 = 2 x 2 = 4
milli-moles of HNO3 left = 5 -4 = 1
Now, total volume = 100+ 100 = 200 mL
It is asked for hydronium ion concentration, which is basically hydrogen ion conc.
1 HNO3 will dissociate to give 1 H+ ion.
so, milli-moles of H+ = 1
So, concentration of H+ or hydronium(H3O+) = 1 / 200 = 0.005