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astra-53 [7]
3 years ago
5

A thermographic camera or thermal imaging camera is a device that

Physics
1 answer:
guapka [62]3 years ago
6 0

Answer:

<u><em></em></u>

  • <u><em>Using thermal imaging to detect heat energy loss through the roof and windows.</em></u>

<u><em></em></u>

Explanation:

<em>Heat energy</em> is transmitted by conduction, convection, and <em>radiation</em>.

All warm objects emit heat energy in the form of infrared <em>radiation</em>, which is a kind of invisible light (light with a lower frequency and longer wavelentgh than the visible light).

The amount of heat energy emitted by an object is proportional to its temperature: the higher the temperature of the object body, the greater the amount of radiant energy emitted.

A<em> house </em>can loss heat energy by radiation through the walls, <em>roof and windows.</em>

<em>A thermographic camera or thermal imaging camera </em>will detect the infrared radiation emitted through walls, roof and windows, showing a red image in those areas.

I found the image attached in internet, showing the red areas around the roof and windows of a house, mainly, using a thermal imaging camera.

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Charge Q is distributed uniformly throughout the volume of an insulating sphere of radius R = 4.00 cm. At a distance of r = 8.00
Elena L [17]

Answer:

2.62898\times 10^{-6}\ C/m^3

1979.99974\ N/C

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

Q = Charge

r = Distance = 8 cm

R = Radius = 4 cm

Electric field is given by

E=\dfrac{kQ}{r^2}\\\Rightarrow Q=\dfrac{Er^2}{k}\\\Rightarrow E=\dfrac{990\times 0.08^2}{8.99\times 10^{9}}\\\Rightarrow Q=7.04783\times 10^{-10}\ C

Volume charge density is given by

\sigma=\dfrac{Q}{\dfrac{4}{3}\pi R^3}\\\Rightarrow \sigma=\dfrac{7.04783\times 10^{-10}}{\dfrac{4}{3}\pi (0.04)^3}\\\Rightarrow \sigma=2.62898\times 10^{-6}\ C/m^3

The volume charge density for the sphere is 2.62898\times 10^{-6}\ C/m^3

E=\dfrac{kQr}{R^3}\\\Rightarrow E=\dfrac{8.99\times 10^9\times 7.04783\times 10^{-10}\times 0.02}{0.04^3}\\\Rightarrow E=1979.99974\ N/C

The magnitude of the electric field is 1979.99974\ N/C

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I hope this helps. ^-^

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