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jek_recluse [69]
3 years ago
5

Implement A* graph search. A* takes a heuristic function as an argument. Heuristics

Computers and Technology
1 answer:
svetlana [45]3 years ago
7 0
It may be the reason
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All queries have an explicit location. true of false
astraxan [27]
This statement is false

7 0
3 years ago
Read 2 more answers
Define a function below called average_strings. The function takes one argument: a list of strings. Complete the function so tha
tester [92]

Answer:

def average_strings(lst):

   total_length = 0

   avg = 0

   for s in lst:

       total_length += len(s)

   avg = total_length/len(lst)

   return avg

Explanation:

Create a function called average_strings that takes one parameter, lst

Initialize the total length and avg variables

Create a for loop that iterates through the lst. Get each string's length and put it to the total length

When the loop is done, calculate the average, divide total length by length of the lst

Return the average

6 0
4 years ago
Write a filter that reads in a sequence of integers and prints the integers, removing repeated values that appear consecutively.
lara31 [8.8K]

Answer:

Following is the code for filter:

public class filter

{ public static void main(String[] args)

{ int x = StdIn.readInt();

System.out.print(" " + x + " ");

while(!StdIn.isEmpty())

{ int y = StdIn.readInt();

    if(y != x)

          System.out.print(" " + y + " ");

    x = y;

    }

    }

    }

Explanation:

  • A public class filter is used.
  • The main function will accept a single argument as string[], it is also known as java command line argument.
  • Now the Stdln.readInt is used to read the integers in the sequence and store it in integer x.
  • The value stored in variable x will be printed using System.out.print
  • Now unless the Stdln.readInt gets an empty value, check each value of sequence and store in variable y.
  • If y is not equal to previous value x, print it and shift the value of y into x.
  • Repeat the loop again.

i hope it will help you!

7 0
3 years ago
Read 2 more answers
Consider a classful IPv4 address 200.200.200.200? What is its implied subnet mask? If we take the same address and append the CI
topjm [15]

Answer:

a. 255.255.255.0 (class C)

b. 255.255.255.224

Explanation:

Here, we want to give the implied subnet mask of the given classful IPV4 address

We proceed as follows;

Given IPv4 address: 200.200.200.200

Classes

Class A : 0.0.0.0 to 127.255.255.255

Class B: 128.0.0.0 to 191.255.255.255

Class C: 192.0.0.0 to 223.255.255.255

Class D: 224.0.0.0 to 239.255.255.255

so 200.200.200.200 belongs to Class C and it's subnet mask is 255.255.255.0

In CIDR(Classless Inter Domain Routing)

subnet /27 bits means 27 1s and 5 0s. so subnet

i.e 11111111.11111111.11111111.11100000 which in dotted decimal format is 255.255.255.224 .

4 0
3 years ago
Um?<br><br> i went to check my questions and i found this-
asambeis [7]

Answer:

just go ahead and refresh the page

Explanation:

5 0
3 years ago
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