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3 years ago

8

An object’s

2 answers:

Ket [755]3 years ago

7 0

Answer:

mass, weight, strength of gravity increases, weight decreases

Explanation:

got it on edge

Roman55 [17]3 years ago

6 0

Answer:

Explanation:

An object’s mass will remain constant throughout the universe, but its WEIGHT can change from planet to planet.

If you increase the mass of a planet, what happens to its gravity?

If the radius does not change, Then its gravity increases.

If the gravity on a planet decreases, what happens to the weight of an object on that planet? Weight decreases.

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An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane travel

Licemer1 [7]

Answer:

$v=4.44\frac{m}{s}$

Explanation:

Given that the airplane starts from the rest (this is initial velocity equals to zero) and accelerates at a constant rate, position can be described like this: $x=v_{0}t +\frac{1}{2} at^{2}$ where x is the position, t is the time a is the acceleration and $v_{0}$ is initial velocity. In this way acceleration can be found. $a=\frac{2(x-v_{0}t) }{t^{2} } =\frac{2(1.11m-0)}{1s^{2} } =2.22\frac{m}{s^{2} }$ .

Now we are able to found velocity at any time with the formula: $v=v_{0} +at = 0\frac{m}{s} +(2.22\frac{m}{s^{2}}.2s)=4.44\frac{m}{s}$

3 0

3 years ago

How does it do? this photo

vova2212 [387]

Answer: Its A because i had the same question and it was a

5 0

3 years ago

Read 2 more answers

Which of the following is an example of chemical change?

Maru [420]

Answer:

c

Explanation:

all the others r physical

8 0

3 years ago

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The angular velocity (in rpm) of the blade of a blender is given in. If θ=0rad at t=0s, what is the blade's angular position at

Liula [17]

Answer:

θ = 20.9 rad

Explanation:

In a blender after a short period of acceleration the blade is kept at a constant angular velocity, for which we can use the relationship

w = θ / t

θ = w t

if we know the value of the angular velocity we can find the angular position, we must remember that all the angles must be in radians

suppose that the angular velocity is w = 10 rpm, let us reduce to the SI system

w = 10 rpm $(\frac{2\pi rad}{1 rev}) ( \frac{1 min}{60 s} )$

= 1,047 rads

let's calculate

θ = 1,047 20

θ = 20.9 rad

7 0

3 years ago

A thin soap bubble of index of refraction 1.33 is viewed with light of wavelength 550.0nm and appears very bright. Predict a pos

faust18 [17]

Answer:

The possible thickness of the soap bubble = $1.034\times 10^{-7}\ m.$

Explanation:

<u>Given:</u>

Refractive index of the soap bubble, $\mu=1.33.$
Wavelength of the light taken, $\lambda = 550.0\ nm = 550.0\times 10^{-9}\ m.$

Let the thickness of the soap bubble be $t$ .

It is given that the soap bubble appears very bright, it means, there is a constructive interference takes place.

For the constructive interference of light through a thin film ( soap bubble), the condition of constructive interference is given as:

$2\mu t=\left ( m+\dfrac 12 \right )\lambda.$

where $m$ is the order of constructive interference.

Since the soap bubble is appearing very bright, the order should be 0, as $0^{th}$ order interference has maximum intensity.

Thus,

$2\mu t=\left (0+\dfrac 12\right )\lambda\\t=\dfrac{\lambda}{4\mu}\\\ \ = \dfrac{550\times 10^{-9}}{4\times 1.33}\\\ \ = 1.034\times 10^{-7}\ m.$

It is the possible thickness of the soap bubble.

6 0

3 years ago