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WARRIOR [948]
3 years ago
6

Catalytic converters reduce the engine's tailpipe emissions of unburned hydrocarbons and carbon monoxide and

Engineering
2 answers:
brilliants [131]3 years ago
7 0
This is true. If your catalytic converters are removed off your vehicle it will cause you to run rich cause of the unspent fuel.
puteri [66]3 years ago
5 0

Answer:

True

Explanation:

Below is a cut and paste.  Also read where recycling shops will pay up to $200 to harvest the precious metals used in catalyst process.  Thieves will actually steal them from parked cars!!

Catalytic converters also use an oxidative catalyst composed of platinum or palladium. It helps reduce hydrocarbons (HC) and carbon monoxide (CO). To start with, carbon monoxide and oxygen combine to form carbon dioxide (CO2). Then, unburnt hydrocarbons and oxygen combine to form carbon dioxide and water.

Oxidation reactions for carbon monoxide and unburned hydrocarbons

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Germanium forms a substitutional solid solution with silicon. Compute the number of germanium atoms per cubic centimeter for a g
brilliants [131]

Answer:

The number of germanium atoms per cubic centimeter for this germanium-silicon alloy is 3.16 x 10²¹ atoms/cm³.

Explanation:

Concentration of Ge (C_{Ge}) = 15%

Concentration of Si (C_{Si}) = 85%

Density of Germanium (ρ_{Ge}) = 5.32 g/cm³

Density of Silicon (ρ_{Si}) = 2.33 g/cm³

Atomic mass of Ge (A_{Ge})= 72.64 g/mol

To calculate the number of Ge atoms per cubic centimeter for the alloy, we will use the formula:

No of Ge atoms/cm³=[Avogadro's Number*C_{Ge}]/([C_{Ge}*A_{Ge}/ρ_{Ge})+(C_{Si}*A_{Ge}/ρ_{Si})]

                              = (6.02x10²³ * 15%) / [(15% * 72.64/5.32)+(72.64*85%/2.33)]

                              = (9.03x10²²)/(2.048+26.499)

                              = (9.03x10²²)/(28.547)

No of Ge atoms/cm³ = 3.16 x 10²¹ atoms/cm³

3 0
3 years ago
What do you own that might not be manufactured?
horrorfan [7]

Answer:

A pet

Explanation:

Latin time I checked animals aren't made by people? I honestly don't know if this helps but I'm technically not wrong.

8 0
3 years ago
Type the correct answer in the box. Spell all words correctly. Elaine is an engineer. She has to create a prototype of a machine
Trava [24]

Answer:

the mean time I was wondering if you have any questions or need any further information please contact me at the mean time I was

8 0
3 years ago
the highway department is to design a roadway over a swamp area. the swamp consists of very soft fine-grained soils obviously sa
garik1379 [7]

I'd like to propose that the embankment be built in stages. Because of the possibility of abrupt coloase of structure in swampy places. Soil carrying capacity is extremely low in those places. You must first densify the soil and make it acceptable using various procedures such as grouting, vibrification, restricting, and so on. These types of jobs are critical during the earliest stages of embankment development. After that, we can begin our construction work.

What is soil?

Soil, often known as earth or soil, is a complex mixture of organic matter, minerals, gases, liquids, and creatures that support life. Some scientific definitions distinguish dirt from soil by limiting the former term to displaced soil only. Soil is made up of two phases: a solid phase of minerals and organic matter and a porous phase that retains gases and water. As a result, soil is a three-state system composed of solids, liquids, and gases. Soil is the result of various elements interacting throughout time, including climate, relief, creatures, and the parent components of the soil.

To learn more about soil
brainly.com/question/28201561

#SPJ4

5 0
1 year ago
A soil specimen was tested to have a moisture content of 32%, a void ratio of 0.95, and a specific gravity of soil solids of 2.7
belka [17]

Answer:

a. 0.9263

b. 0.4872

c. 13.83kN/m^{3}

Explanation:

moisture content (ω) = 0.32

void ratio (e) = 0.95

specific gravity (G_{s}) = 2.75

the degree of satruation (S) = \frac{w . G_{s} }{e} =0.32×2.75/0.95 = 0.9263

b. porosity (n) = \frac{e}{e + 1} = 0.95/(0.95 + 1)= 0.4872

c. dry unit weight (γ_{d}) = \frac{G_{s} . V_{w} }{1 + e}

taking specific unit weight of water (V_{w})= 9.81kN/m^{3}

γ_{d} = 2.75 × 1000/(1 + 0.95) = 13.83kN/m^{3}

5 0
3 years ago
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