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andrew-mc [135]
3 years ago
11

Determine whether AB ← → and CD ← → − are parallel, perpendicular, or neither. A(-6, 2), B(−3, -4), C(1, -3), D(3, 4)

Mathematics
1 answer:
guapka [62]3 years ago
6 0
Neither they connect but don’t make a 90 degree angle

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How do i graph the lines when the equations aren’t in slope intercept form????
jekas [21]

Slope-Intercept Form: y=mx+b

Standard Form: ax+by=c

Point- Slope: (y-y1)= m(x-x1)

There are multiple answers to your question-

  1. If you are only missing b(the y-intercept) but are given a set of points, plug the points into x and y and solve for b.
  2. If you are only missing the slope(m) but are given a set of points, plug the points into x and y and solve for m.
  3. If you are given the standard form/point-slope form, change the equation to slope intercept form.
  4. If you are given an complete form(there is an x and y; no missing variables), but are not sure what it is, plug in some numbers in x to find y, then graph.
7 0
3 years ago
I would appreciate some help on this if anyone could answer it
Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

yea

7 0
3 years ago
I met a man who said, if you can guess my age, I will pay you one dollar for each year that I have lived . I will also give you
Vladimir79 [104]
He could be 40321 years old.
If you divide 40321 by any odd or even number between 1 and 9, the remainder is 1.

I got this number by doing (2*3*4*5*6*7*8) + 1
4 0
3 years ago
Read 2 more answers
If cos A = k, then the value of the expression (sin A)(cos A)(tan A) is equivalent to:
sukhopar [10]

Answer:

1-k^2

Step-by-step explanation:

tan A= sin A/cos A

(sin A)(cos A)(sin A/cos A)=(sin A)^2

(sin A) ^2 + (cos A) ^2= 1

(sin A) ^2=1-(cos A) ^2

(sin A)^2= 1 - k^2

4 0
2 years ago
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A van travels at a constant speed of x km/hr over a distance of 45km/hr. If the van increases its speed by 4km/h, it will be abl
harkovskaia [24]
Speed = Distance/Time. Let speed be V, distance D and time T

a)Given: D₁ =45km, V₁=x km/h 
V₁=D₁/T
V₁=45/T OR T= 45/V₁

b) Given : D₂ =48 km and V₂ = V₁ + 4 km/h
V₂ = 48/T, but V₂ = V₁+4, then:

V₁+4 = 48/T OR  T=48/(V₁+4). Since Time is same, then we can write:
45/V₁ =48/(V₁+4), solve for V₁:
45V₁ + 180 = 48V₁

3V₁ =180 and V₁ = x = 60 km/h
8 0
3 years ago
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