Determine whether AB ← → and CD ← → − are parallel, perpendicular, or neither. A(-6, 2), B(−3, -4), C(1, -3), D(3, 4)

Determine what the solution is to the following system? Y=3/4x-1 & y=4/3x-1

vichka [17]

Answer:

(0, -1)

Step-by-step explanation:

There are multiple ways of solving this however- since both equations are already in Y-Intercept form, we will use the "Equal Values Method"

First, since both equations are equal to Y, we can set them equal to each other and solve for X

$\frac{3 }{4} x - 1 = \frac{4}{3} x - 1$

To start, you must eliminate the fraction using a "fraction buster" multiply EVERYTHING by 4 then simplify.

$3x - 4 = 5 \frac{1}{3}x - 4$

Since we still have a fraction, we shall do it one more time. This time we multiply by 3

$9x - 12 = 6 x - 12$

Now, solve how you normally would.

9x = 6x

-6x

3x = 0

X = 0

Now, since we know what X would equal in the solution, we are able to plug in X as 0 in one of our equations. We can choose the first one!

$y = \frac{3}{4} (0) - 1$

Now solve which would lead to y = -1

You have your solution as

(X,Y)

(0,-1)

Hope this helps!

4 0

3 years ago

Is 7 - -4 positive or negative?<br> positive<br> negative

djverab [1.8K]

Answer:

Positive.

Step-by-step explanation:

When you see two negative signs directly next to each other (as shown in the given expression), it will become a positive sign:

7 - (-4) = 7 + 4 = 11

Positive is your answer.

* To be fair, even if there is only one negative sign, the answer will still be positive, however, I am assuming you are suggesting only the sign, and not the answer.

~

7 0

3 years ago

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

a

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

b

$F_{critical} = 1.8608$

c

$F = 2.9085$

d

The decision rule is

Reject the null hypothesis

e

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is