Answer:
11.7 im pretty sure. i did the work so it should be correct
Answer:
Explanation:
Let the specific heat of material be s
heat lost by material = m₁ s (T 1 - T ) , (T 1 - T ) is fall in temp , m₁ is mass of material
= .45 x s x (91 - 31.4 )
= 26.82 s
Heat gained by water
= m₂ cw (T2 - T )
1.3 x 4186 x ( 31.4 - 23 )
heat lost = heat gained
m₂ cw (T2 - T ) = m₁ s (T 1 - T )
1.3 x 4186 x ( 31.4 - 23 ) = .45 x s x (91 - 31.4 )
45711.12 = 26.82 s
s = 1704.36
25,000 Feet = 7620m
PE = mgh where m is mass, g is gravity accel: 9.8 n h is height
= 90 x 9.8 x 7620
= 6720840J
= 6.72MJ
F = ma where m is mass, a is accel = gravity = 9.8
= 90 x 9.8
= 882N
Accel = gravity = 9.8m/s^2
KE = 1/2mv^2 where m is mass n v is vel
if no wind resistance, PE leaving airplane = KE at net
6720840 = 1/2 x 90 x v^2
v^2 = 149352
v = 386.5m/s
