Look first for the relation between deBroglie wavelength (λ) and kinetic energy (K):
K = ½mv²
v = √(2K/m)
λ = h/(mv)
= h/(m√(2K/m))
= h/√(2Km)
So λ is proportional to 1/√K.
in the potential well the potential energy is zero, so completely the electron's energy is in the shape of kinetic energy:
K = 6U₀
Outer the potential well the potential energy is U₀, so
K = 5U₀
(because kinetic and potential energies add up to 6U₀)
Therefore, the ratio of the de Broglie wavelength of the electron in the region x>L (outside the well) to the wavelength for 0<x<L (inside the well) is:
1/√(5U₀) : 1/√(6U₀)
= √6 : √5
Answer:
Q1 = +2.50 x 10^-5C and Q2 = -2.50 x 10^-5C, r = 0.50m, F=?
Using Coulomb's law:
F = 1/(4πE) x Q1 x Q2/ r^2
Where
k= 1/(4πE) = 9 x 10^9Nm2/C2
Therefore,
F = 9x 10^9 x 2.50 x 10^-5 x2.50 x
10^-5/. ( 0.5)^2
F= 5.625/ 0.25
F= 22.5N approximately
F= 23N.
To find the direction of the force: since Q1 is positive and Q2 is negative, the force along Q1 and Q2 is force of attraction.
Hence To = 23N, attractive. C ans.
Thanks.
EC_1 + EP_1 = EC2 + EP_2
EC_2 = 0
EC_2 = EP_1 - EP_2
EC_2 = mg(H_1 - H_2) = 0.20 kg * 9.8 m/s^2 * (3.25 m - 1.5m) = 3.43 J
Answer:
simple
Explanation:
<h3>CONCAVE MIRRORS AND LENSES</h3>
<h3>f= negative</h3>
<h3>CONVEX MIRRORS AND LENSES</h3><h3 /><h3>f= positive</h3>
<h3>PLEASE FOLLOW ME AND MARK IT BRAINLIEST</h3>
0.31m/s
Explanation:
Given parameters:
Time of travel = 4hrs = 4 x 60 x 60 = 14400s
Displacement = 4400m due west
Unknown:
Velocity = ?
Solution:
Velocity is defined as the displacement per unit of time. It is expressed in m/s or km/hr:
Velocity = 
Velocity =
= 0.31m/s
Learn more:
Velocity brainly.com/question/10883914
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