Answer:
8451.62109367671 Newtons
Explanation:
It is known that
So,
The force in Newtons is 8451.6210936765 Newtons
Refer to the diagram shown below.
μ = the coefficient of dynamic friction between the crate and the ramp.
1. The applied force of F acts over a distance, d.
The work done is F*d.
2. The component of the weight of the crate acting down the ramp is
mg sin(30) = 0.5mg.
The work done by this force is 0.5mgd.
3. The normal force is N = mgcos(30) = 0.866mg.
This force is perpendicular to the ramp, therefore the work done is zero.
4. The frictional force is μN = μmgcos(30) = 0.866μmg.
The work done by the frictional force is 0.866μmgd.
5. The total force acting on the crate up the ramp is
F - mgsin(30) - μmgcos(30) = F - mg(0.5 - 0.866μ)
6. The work done on the crate by the total force is
d*(F - 0.5mg - 0.866μmg)
Answer:
<em>The cantaloupe has a speed of 117.6 m/s</em>
Explanation:
<u>Free Fall Motion</u>
It occurs when an object falls under the sole influence of gravity. Any object that is being acted upon solely by the force of gravity is said to be in a state of free fall. Free-falling objects do not face air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is .
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The cantaloupe has been dropped from rest. We are required to find the speed after t=12 seconds.
Calculate the final speed:
vf=9.8 * 12 = 117.6 m/s
The cantaloupe has a speed of 117.6 m/s
Answer:
See below
Explanation:
9.7e-6 is 9.7 x 10^-6 move the decimal 6 to the LEFT to get
= .0000097
Answer:
density = 0.0933 kg/m
speed = 27.581 m/s
Explanation:
given data
length L = 4.5 m
mass m = 0.42 kg
force F = 71 N
to find out
mass density and speed
solution
we find linear mass density
linear mass density = mass / length
put here all value
density = 0.42 / 4.5
density = 0.0933 kg/m
and
speed of wave
speed = √(F/density)
speed = √(0.42/0.933)
speed = 27.581 m/s