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3 years ago

What season is represented in the northern hemisphere? *

Chemistry

1 answer:

luda_lava [24]3 years ago

4 0

Answer:

B. summer

Explanation:

The northern hemisphere experiences summer during the months of June, July, and August because it is tilted toward the sun and receives the most direct sunlight.

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What is the rate law for the uncatalyzed reaction?

elena55 [62]

What is the rate law for the uncatalyzed reaction?

Metals often form several cations with different charges. Cerium, for example, forms and ions, and thallium forms and ions. Cerium and thallium ions react as follows:

2Ce^4+(aq) + Tl^+(aq) ---> 2Ce^3+(aq)+Tl^3+(aq)

This reaction is very slow and is thought to occur in a single elementary step. The reaction is catalyzed by the addition of Mn^2+ according to the following mechanism:

Ce^4+(aq)+Mn^2+(aq) ---> Ce^3+(aq)+Mn^3+(aq)

Ce^4+(aq)+Mn^3+(aq) ---> Ce^3+ (aq) + Mn^4+ (aq)

Mn^4+(aq) + Tl^+(aq) ---> Mn^2+(aq) + Tl^3+(aq)

If the uncatalyzed reaction occurs in a single elementary step, why is it a slow reaction?

1)The probability of an effective three-particle collision is low.

2) The transition state is low in energy.

3) The reaction requires the collision of three particles with the correct energy and orientation.

4) All reactions that occur in one step are slow.

The catalyzed reaction is first order in [Ce^4+] and first order in [Mn^2+]. Which of the steps in the catalyzed mechanism is rate determining?

Based on their available oxidation states, rank the following metals on their ability to catalyze this and other oxidation-reduction reactions.

Rank from best to worst catalyst.

Vanadium, titanium, manganese

4 0

3 years ago

Read 2 more answers

Rank the following substances in order from most soluble in water to least soluble in water: methane, CH4; 2-butanol, C4H9OH; ma

Taya2010 [7]

Answer: The given substances are placed in order from most soluble in water to least soluble in water as follows.

$MgCl_{2}$ > $C_{4}H_{9}OH$ > $C_{3}H_{8}$ > $CH_{4}$

Explanation:

It is known that like dissolves like which means a polar compound will be soluble in a polar solvent. And, a non-polar compound will be soluble in non-polar solvent.

Ionic compounds are soluble in polar solvent like water. For example, $MgCl_{2}$ is an ionic compound and it is readily soluble in water.

2-butanol ( $C_{4}H_{9}OH$ ) is also a polar compound and it will also dissolve in water but to a lesser extent as compared to magnesium chloride.

Whereas both methane and propane are non-polar in nature. But as propane is larger in size as compared to methane so, it will be slightly more soluble in water as compared to methane.

Thus, we can conclude that the given substances are placed in order from most soluble in water to least soluble in water as follows.

$MgCl_{2}$ > $C_{4}H_{9}OH$ > $C_{3}H_{8}$ > $CH_{4}$

5 0

3 years ago

1+1 hahahahahhhahahaahahahahahahahahahahahahahaha why u dumb

-Dominant- [34]

Answer:

1+1=2 Unless this is a trick question. Then it's most likely 11.

Explanation:

4 0

2 years ago

Read 2 more answers

Active and inactive volcano in philipines?

finlep [7]

355 volcanoes in the Philippines are inactive.

24 volcanoes are active

3 0

3 years ago

Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o

jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

Step 1: The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

Step 2: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

Step 3: Calculate moles of glucose

Moles glucose = Mass glucose / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

Step 4: Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

Step 5: Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

Step 6: Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0

3 years ago