Answer:
The difference of head in the level of reservoir is 0.23 m.
Explanation:
For pipe 1

For pipe 2

Q=2.8 l/s
![Q=2.8\times 10^{-3]](https://tex.z-dn.net/?f=Q%3D2.8%5Ctimes%2010%5E%7B-3%5D)
We know that Q=AV




head loss (h)

Now putting the all values

So h=0.23 m
So the difference of head in the level of reservoir is 0.23 m.
Remote?? maybe I’m not really sure
Answer:
a) 246.56 Hz
b) 203.313 Hz
c) Add more springs
Explanation:
Spring constant = 12000 N/m
mass = 5g = 5 * 10^-3 kg
damping ratio = 0.4
<u>a) Calculate Natural frequency </u>
Wn = √k/m = 
= 1549.19 rad/s ≈ 246.56 Hz
<u>b) Bandwidth of instrument </u>
W / Wn = 
W / Wn = 0.8246
therefore Bandwidth ( W ) = Wn * 0.8246 = 246.56 * 0.8246 = 203.313 Hz
C ) To increase the bandwidth we have to add more springs
Answer:
Production Function : TFSq = f { ingredient 1 ...... ing. i }
Increasing/ Constant/ Increasing Returns to Scale :
Output change > / = / < Input change respectively
Explanation:
Production Function is the relationship between production inputs & outputs, given technology. It denotes the maximum output that can be generated with given inputs.
Tutti Frutti Smoothie [TFS] quantity = Function of {Ingredient1.....ingredient i}
Returns to Scale represents change in output when all inputs change in same proportion.
- Constant Returns to Scale [CRS] : Output Change = All inputs change
- Increasing Returns to Scale [IRS] : Output Change > All inputs change
- Negative Returns to Scale [NRS] : Output Change < All inputs change
When all inputs (ingredients) change by same proportion i.e get twice 2X :- If output of Tutti Frutti Smoothie increases by > 2X i.e 3X - IRS. If it increases equal ie 2X - CRS. If it increases lesser i.e 1.5X - CRS.