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ELEN [110]
3 years ago
9

In a titration of monoprotic acids and bases, there is a large change in pHA. at the point where pH = pKa of the acid.B. when th

e volume of acid is exactly equal to the volume of base.C. when the concentration of acid is exactly equal to the concentration of base.D. when the number of moles of acid is exactly equal to the number of moles of base.E. at the point where pH = pKb of the
Chemistry
1 answer:
Jobisdone [24]3 years ago
3 0

Answer:

D. when the number of moles of acid is exactly equal to the number of moles of base.

Explanation:

<em>Regarding options A. and E</em>., pKa and pKb would only be taken into consideration if the titrations were of <em>weak</em> acids and bases. However it is possible to have a titration of monoprotic acids and bases with strong acids and bases.

Another way of looking at the answer is identifying <em>which one best describes the equivalence point</em>.

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mr_godi [17]
No, physics does not suggest an exact pace in which a chemical compound will travel. It will matter in external forces as well as the median it is travelling through.

7 0
3 years ago
A student needs to prepare 100. mL of 0.612 M Cu(NO3)2 solution. What mass, in grams, of copper(II) nitrate should the student u
Temka [501]

Answer: 11.5 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution

Molarity=\frac{n\times 1000}{V_s}

where,

Morality = 0.612 M

n= moles of solute  

V_s = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

0.612=\frac{n\times 1000}{100ml}

n=0.0612moles

Mass={\text {moles of solute }}{\times {\text {molar mass}}=0.0612moles\times 187.56g/mol=11.5g

Therefore, the mass of copper (II)nitrate required is 11.5 grams

3 0
3 years ago
Select the TRUE statements below regarding the coordination compound prepared in lab. Group of answer choices The coordination c
Vanyuwa [196]

Answer: Hello the compound is missing but I was able to get the Full question and missing compound . ( compound = copper sulfate )

<em>answer</em> : statement ; 2 , 3 and 5

Explanation:

The true statements regarding the coordination compound ( copper sulfate ) are :

  • The ligand must have at least one unshared pair of valence electrons in order to covalently bond with transition metal in the coordination compound ( statement 2 )
  • Ethanol was used during crystallization of the coordination compound because the compound is soluble in ethanol ( statement 3 )
  • The colors of many coordination compounds are the result of light absorption by the d electrons on the transition metal ( statement 5 )

During the coordination of compounds dative bonds exits between the transition metals and the Ligands molecules

7 0
3 years ago
Balanced chemical equation: BaCl2(aq)+Na2SO4(aq)⟶BaSO4(s)+2NaCl(aq)
Ipatiy [6.2K]

Answer:

Part 1)  85.3 grams NaCl

Part 2)  8.79 x 10²³ formula units NaCl

Explanation:

<u>(Part 1)</u>

To find the mass of NaCl, you need to multiply the given value (1.46 moles) by the molar mass of NaCl. This measurement is the atomic masses of the elements times each of their quantities combined. In this case, there is only one mole of each element in the molecule. Moles should be located in the denominator of the conversion to allow for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (NaCl): 22.99 g/mol + 35.45 g/mol
Molar Mass (NaCl): 58.44 g/mol

1.46 moles NaCl            58.44 g
---------------------------  x  ----------------  =  85.3 grams NaCl
                                        1 mole

<u>(Part 2)</u>

I do not know which other question the second part is referring to, so I will just use the moles given in the first part. To find the formula units, you need to multiply the given value (1.46 moles NaCl) by Avogadro's Number. This conversion represents the number of formula units found in 1 mole of the sample. The moles should be in the denominator of the conversion to allow for the cancellation of units.

Avogadro's Number:

1 mole = 6.022 x 10²³ formula units

1.46 moles NaCl         6.022 x 10²³ units
------------------------  x  -----------------------------  =  8.79 x 10²³ formula units NaCl
                                          1 mole

4 0
2 years ago
What is the major use of carbon monoxide
Dmitry [639]

Answer:

Carbon monoxide is a very important industrial compound. In the form of producer gas or water gas.

hope ths help and if you want more information go to this website: science.jrank.org

8 0
2 years ago
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