The area of the garden enclosed by the fencing is
A(x, y) = xy
and is constrained by its perimeter,
P = x + 2y = 200
Solve for x in the constraint equation:
x = 200 - 2y
Substitute this into the area function to get a function of one variable:
A(200 - 2y, y) = A(y) = 200y - 2y²
Differentiate A with respect to y :
dA/dy = 200 - 4y
Find the critical points of A :
200 - 4y = 0 ⇒ 4y = 200 ⇒ y = 50
Compute the second derivative of A:
d²A/dy² = -4 < 0
Since the second derivative is always negative, the critical point is a local maximum.
If y = 50, then x = 200 - 2•50 = 100. So the farmer can maximize the garden area by building a (100 ft) × (50 ft) fence.
Answer:
The correct option is A. The height of tree is 60 ft.
Step-by-step explanation:
From the given figure it is noticed that the building is creating a right angle triangle from a point and the tree divides the hypotenuse and base in two equal part.
According to midpoint theorem of triangle: In a triangle, if a line segment connecting the midpoints of two sides, then the line is parallel to third side. The length of line segment is half of the length of third side.
Using midpoint theorem of triangle, we can say that the length of tree is half of the building.



Therefore correct option is A. The height of tree is 60 ft.
The quadratic equation could be:
Half dollar = 50
quarter=25
dime=10
nickel=5
penny=1
what are you trying to find out ? im lost
Liam = 4t = 5.50
Zachary = 3t = 6.50
7t = 12.00
t = 12.00/7
t = 1.71
T= price of the taco spend the same amount