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3 years ago

Select all the expressions that represent the large rectangle's total area.

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

6 0

B, C and D are all correct

tangare [24]3 years ago

5 0

B, C, D are the correct answers good luck

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Find all solutions to the equation. cos^2x + 2 cos x + 1 = 0

garri49 [273]

Answer:

take a picture of the problem

3 0

3 years ago

Suppose that the number of cars manufactured at an automobile plant varies jointly as the number of workers and the time they wo

natulia [17]

c = w * t*k

198 = 220*5k

198------ = k = .18220(5)

c = .18(175)(6) = 189

3 0

3 years ago

Read 2 more answers

Suppose that the lifetime of tv tubes are normally distributed with a standard deviation of 1.1 years. Suppose that exactly 20%

IrinaK [193]

Answer:

4.924 years

Step-by-step explanation:

Lets denote X the lifetime of a tv tube (In years). X has distribution $N(\mu, 1.1)$ , with $\mu$ unknown.

We know that P(X < 4) = 0.2. Using this data, we can find the value of $\mu$ throught standarization.

Lets call $Z = \frac{X - \mu}{1.1}$ the standarization of X. Z has distribution N(0,1), and its cummulative function, $\phi$ is tabulated. The values of $\phi$ can be found in the attached file.

$P(X < 4) = P(\frac{X - \mu}{1.1} < \frac{4 - \mu}{1.1}) = P(Z < \frac{4 - \mu}{1.1}) = \phi(\frac{4 - \mu}{1.1}) = 0.2$

The value q such that $\phi (q) = 0.2$ doesnt appear on the table. We can find it by using the symmetry of the normal density function. The opposite of q, -q must verify that $\phi(-q) = 0.8$ , hence -q must be equal to 0.84. Thus, q = -0.84

But this value of q should match with the number $\frac{4 - \mu}{1.1}$ , so we have

$\frac{4- \mu}{1.1} = -0.84$

$4 - \mu = 1.1 * (-0.84) = -0.924$

$\mu = 4 - (-0.924) = 4.924$

Thus, the expected lifetime of TV tubes is 4.924 years.

I hope this works for you!

Download pdf

7 0

4 years ago

Which function forms a geometric sequence when x = 1, 2, 3, ...?

jeka94

The geometric sequence is found in the relationship between consecutive terms that is constant.
In this problem, as I understand it, none of the functions forms a geometric sequence.
The functions that form a geometric sequence have the form
f (x) = h (a) ^ n where "a" is the constant relation between the successive terms.
If you wrote the function "f (x) = - 2 (3/4) x", you wanted to write instead:
f (x) = - 2 (3/4) ^ x
So that would be the function that forms a geometric sequence, where the relation between the consecutive terms is 3/4.
You can test it by dividing f (x) / f (x-1)
Then you will see that the result of that division will be 3/4.

4 0

4 years ago

64+16x^2-72x+81=289 I don’t understand

7nadin3 [17]

Answer:

x = 6 or x = -3/2

Step-by-step explanation:

Solve for x:

16 x^2 - 72 x + 145 = 289

Hint: | Write the quadratic equation in standard form.

Divide both sides by 16:

x^2 - (9 x)/2 + 145/16 = 289/16

Hint: | Solve the quadratic equation by completing the square.

Subtract 145/16 from both sides:

x^2 - (9 x)/2 = 9

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 81/16 to both sides:

x^2 - (9 x)/2 + 81/16 = 225/16

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x - 9/4)^2 = 225/16

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x - 9/4 = 15/4 or x - 9/4 = -15/4

Hint: | Look at the first equation: Solve for x.

Add 9/4 to both sides:

x = 6 or x - 9/4 = -15/4

Hint: | Look at the second equation: Solve for x.

Add 9/4 to both sides:

Answer: x = 6 or x = -3/2

7 0

3 years ago