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3 years ago

What are the main causes of injuries when using forklifts?

Engineering

1 answer:

Julli [10]3 years ago

4 0

Answer:

1, 3, 4, 5

Explanation:

just did it

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if a current of 5 amps flows through a resistance of 40 ohms, what is the voltage across that resistor

olasank [31]

Answer:

200V

Explanation:

I = 5A

R = 40Ω

V = IR = (5)(40) = 200V

7 0

2 years ago

Which sentence best describes the entire Energy career cluster? O Energy careers involve the generation, transmission, and distr

nadezda [96]

Answer:

Explanation:

i took the test.

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2 years ago

Read 2 more answers

Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m^

Nat2105 [25]

Answer:

The answer is " $\bold{ 259.2 \times 10^{11} }$ ".

Explanation:

The amount of kilograms, which travel in a thick sheet of hydrogen:

$M= -DAt \frac{\Delta C}{ \Delta x} \\\\$

$D =1.0 \times 10^{8} \ \ \ \frac{m^2}{s} \\\\ A = 0.20 \ m^2\\\\t = 1\ \ h = 3600 \ \ sec \\\\$

calculating the value of $\Delta C:$

$\Delta C =C_A -C_B$

$= 2.4 - 0.6 \\\\ = 1.8 \ \ \frac{kg}{m^3}$

calculating the value of $\Delta X:$

$\Delta x = x_{A} -x_{B}$

$= 0 - (5\ mm) \\\\ = - 5 \ \ mm\\\\= - 5 \times 10^{-3} \ m$

$M = -(1.0 \times 10^{8} \times 0.20 \times 3600 \times (\frac{1.8}{-5 \times 10^{-3}})) \\\\$

$= -(1.0 \times 10^{8} \times 720 \times (\frac{1.8}{-5 \times 10^{-3}})) \\\\= -(1.0 \times 10^{8} \times \frac{ 1296}{-5 \times 10^{-3}})) \\\\= (1.0 \times 10^{8} \times 259.2 \times 10^3)) \\\\= 259.2 \times 10^{11} \\\\$

3 0

3 years ago

Vocabulary review for shop

kaheart [24]

Hazard is a possible source of danger

5 0

3 years ago

A freezer is maintained at 20°F by removing heat from it at a rate of 75 Btu/min. The power input to the freezer is 0.70 hp, and

Igoryamba

Answer:

Explanation:

Cop of reversible refrigerator = TL / ( TH - TL)

TL = low temperature of freezer = 20 °F

TH = temperature of air around = 75 °F

Heat removal rate QL = 75 Btu/min

W actual, power input = 0.7 hp

conversion on F to kelvin = (T (°F) + 460 ) × 5 / 9

COP ( coefficient of performance) reversible = (20 + 460) × 5/9 / (5/9 ( ( 75 +460) - (20 + 460) ))

COP reversible = 480 / 55 = 8.73

irreversibility expression, I = W actual - W rev

COP r = QL / Wrev

W rev = QL / COP r where 75 Btu/min = 1.76856651 hp where W actual = 0.70 hp

a) W rev = 1.76856651 hp / 8.73 = 0.20258 hp is reversible power

I = W actual - W rev

b) I = 0.7 hp - 0.20258 hp = 0.4974 hp

c) the second-law efficiency of this freezer = W rev / W actual = 0.20258 hp / 0.7 hp = 0.2894 × 100 = 28.94 %

8 0

3 years ago