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nata0808 [166]
2 years ago
5

What are the main causes of injuries when using forklifts?

Engineering
1 answer:
Julli [10]2 years ago
4 0

Answer:

1, 3, 4, 5

Explanation:

just did it

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As the amplitude decreases in a wave the energy increasesTrue or false
Montano1993 [528]

Answer:

True

Explanation:

To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

7 0
2 years ago
You notice a new associate from another area is not wearing his required safety glasses. This is the second time you've noticed
Zina [86]

If I notice a new associate from another area not wearing his safety glasses then I would warn him to wear it. In case he doesn't wear then I will report the Manager or HR regarding the same. The best that could be done is to not provide him the benefits of health insurance by the company. The least likely thing that would be done is to ignore the fact that he is not wearing a safety glasses.

8 0
2 years ago
Locução adjetiva e de portuges ou istoria
Alexxx [7]
No hablo espanol perdon amigo
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2 years ago
Elena, the marketing manager at a consumer goods company, plans to send out questionnaires to random individuals (consumers) in
motikmotik

Answer:

A. Qualitative

Explanation:

Because they're looking for qualities to change in future products

7 0
3 years ago
A plane wall of length L, constant thermal conductivity k and no thermal energy generation undergoes one-dimensional, steady-sta
KIM [24]

Answer:

Temperature distribution is T(x)=\dfrac{q}{k}(L-x)+T

Heat flux=q

Heat rate=q A  

Explanation:

We know that for no heat generation and at steady state

\dfrac{\partial^2 T}{\partial x^2}=0

\dfrac{\partial T}{\partial x}=a

T(x)=ax+b

a and are the constant.

Given that heat flux=q

We know that heat flux given as

q=-K\dfrac{dT}{dx}

From above we can say that

a= -\dfrac{q}{K}

Alos given that when x= L temperature is T(L)=T

T= -\dfrac{q}{K}L+b

b=T+\dfrac{q}{K}L

So temperature T(x)

T(x)=-\dfrac{q}{K}x+T+\dfrac{q}{K}L

T(x)=\dfrac{q}{k}(L-x)+T

So temperature distribution is T(x)=\dfrac{q}{k}(L-x)+T

Heat flux=q

Heat rate=q A         (where A is the cross sectional area of wall)

   

6 0
3 years ago
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