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3 years ago

In a case where electrical current leakage from the circuit occurs, the GFCI would do the following:

Engineering

1 answer:

Jobisdone [24]3 years ago

5 0

Answer:

Sense the current leakage

Trip the circuit

Cut off the electricity

Explanation:

The correct order is -

Sense the current leakage

Trip the circuit

Cut off the electricity

Reason -

First step has to be taken to sense the electric current leakage without it being detected, it cant be dealt with.

The second step consists of tripping the circuit so at to remove the flow of electricity.

The third step is to Cut the electricity off so to stop the leakage and be safe.

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3 years ago

Read 2 more answers

Magnetic micro-generators are considered for the recovery of mechanical energy from vibrations. a)-True b)- False,

sleet_krkn [62]

Answer:

False

Explanation:

Magnetic micro generators are used to generate power making use of very small generators for generation of electricity and consists of prime movers, electric generators of quite small size or conversion devices in order to convert environmental energy like heat or vibrations into electrical energy and not mechanical energy.

Therefore, magnetic micro generators are not used for the recovery of mechanical energy from vibrations but electrical energy from them.

7 0

3 years ago

In a parallel one-dimensional flow in the positive x direction, the velocity varies linearly from zero at y = 0 to 32 m/s at y =

monitta

Answer:

Ψ = 10(y^2) + c

y = 1.067m

Explanation:

since the flow is one dimensional in positive X direction, the only velocity component is in X, which is denoted by u

while u is a function of y

we find the u in terms of y; u varies linearly wih y

we use similiraty to find the relation

32/1.6 =u/y

u = 20y

Ψ = ∫20ydy

Ψ = 10(y^2) + c

(b)

the flow is half below y = 1.6*(2/3)=1.067 m

this is because at two third of the height of a triangle lies the centroid of triangle. since the velocity profile forms a right angled triangle , its height is 1.6 m . the flow is halved at y = 1.067m

3 0

3 years ago

A room is filled with saturated moist air at 25°C and a total pressure of 100 kPa. If the mass of dry air in the room is 100 kg,

ANTONII [103]

Answer:the mass of water vapor is=d. 2.04 kg

Explanation:

The humidity ratio by mass is given as

x = mw / ma (1)

where

mw = mass of water vapor

ma = mass of dry air

And also humidity ratio by pressure by Ideal Gas Law is given as

x = 0.62198 pw / (pa - pw) (2)

where

pw = partial pressure of water vapor in moist air

pa = atmospheric pressure of moist air

Equating both equation we have that

Humidity ratio = 0.62198 pw / (pa - pw)= mw / ma (3)

From the from the water table at 25°C,

water vapor partial pressure = 23.8 torr

1 atm =760 torr.

1 atm = 101.325 kPa,

So, 760 torr =101.325 kPa,

Therefore 23.8 torr =3.173kPa

Humidity ratio = 0.62198 pw / (pa - pw)= mw / ma

0.62198 x 3.173 / (100-3.173)= mw / 100

1.9736 /96.827=mw/100

0.0204=mw/100

mw=2.04kg

6 0

4 years ago