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kykrilka [37]
3 years ago
7

Question is in picture! Will give extra points and BRAINLIEST! Promise!!! No links or I will report. Make sure it’s a legitimate

answer and not a link

Chemistry
1 answer:
koban [17]3 years ago
8 0
Try to look it up your welcome
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If 3.91 moles of H2 were used, how many moles of NH3 would be made?<br><br> HELP PLEASE ASAP
matrenka [14]

N + H2 → NH3

balance the equation

2N + 3H2 → 2NH3

3H2 → 2NH3

3 : 2

3.91 ÷ 3 = 1.303 mol

1.3 × 2 = 2.606 mol

7 0
3 years ago
Compounds like CCl₂F₂ are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are n
Nataliya [291]

Explanation:

The given data is as follows.

        Specific heat of water = 4.18 J/g^{o}C

        Heat of fusion of water = 334 J/g

        Mass of water = 200 g

On bringing water at 0^{o}C, heat released will be as follows.

            q_{1} = m \times C \times \Delta T

                    = 200 g \times 4.18 J/g^{o}C \times (0 - 15)^{o}C

                    = -12540 J

or,                = -12.540 kJ           (as 1 kJ = 1000 J)

Now, calculate the heat releasedwhen water freezes at 0^{o}C as follows.

                q_{2} = mass \times \text{-heat of fusion}

                         = 200 g \times -334 J/g

                         = -66800 J

or,                      = -66.80 kJ

Therefore, total heat released in freezing water will be as follows.

                     q_{total} = q_{1} + q_{2}

                              = (-12.540 - 66.80) kJ

                              = -79.34 kJ

Hence,

       amount of heat released in freezing water = heat used to vaporize CCl_{2}F_{2}

Now, heat of vaporization of CCl_{2}F_{2} = 289 J/g

Total heat released in freezing water = -79.34 kJ

Heat consumed to vaporize CCl_{2}F_{2} = 79.34 kJ = -79340 J

Therefore, calculate the mass of CCl_{2}F_{2} vaporized as follows.

              Mass of CCl_{2}F_{2} vaporized = \frac{\text{heat consumed}}{\text{heat of vaporization}}

                              = \frac{79340 J}{289 J/g}

                              = 274.53 g

Thus, we can conclude that 274.53 g mass of this substance must evaporate to freeze 200 g of water initially at 15^{o}C.

5 0
4 years ago
What is produced on the top of a pool of water by the mutual attraction between water molecules?
forsale [732]
The answer is surface tension
6 0
3 years ago
Intact cells of two unknown cell types were placed into solutions with different concentrations of NaCl. Type I cells swelled an
Bess [88]

Answer:

Cell Type I: Animal cell surrounded by a plasma membrane only.

Cell Type II: Plant cell surrounded by a plasma membrane and a cell wall.

Explanation:

Hello,

In this case, we must remember that animal cells are covered only by a plasma membrane, which is not enough to keep the cell from bursting as no limit for the inlet salt is established, causing it both to swell and burst. On the other hand, plant cells are covered by both a plasma membrane and a cell wall which contributive effect allow the inlet of the salt but prevent the cell to burst as the cell wall is rigid. In such a way, based on the described situation, one infers that the cell type I is an animal cell surrounded by a plasma membrane only the cell type II is a plant cell surrounded by a plasma membrane and a cell wall.

Best regards.

3 0
3 years ago
Match each chemical with the correct use.
Fittoniya [83]

1. x-ray soft tissue organs  - barium  

2. reduce pain and fever- acetylsalicylic acid

3. anesthetic-  nitrous oxide  

4. treat acne - A. benzoyl peroxide

7 0
4 years ago
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