True or False: Galvanized steel pipe can withstand moderate freezing.

Steam enters a heavily insulated throttling valve at 11 MPa, 600Â°C and exits at 5.5 MPa. Determine the final temperature of the

7nadin3 [17]

Answer: the final temperature of the steam 581.5 °C

Explanation:

Given that;

P₁ = 11 MPa

T₁ = 600°C

exit at; P₂= 5.5 MPa

Now from superheated steam table( p=11 MPa, T=600°C)

h₁ = 3615 kJ/kg

h₁ = h₂ ( by throttling process and adiabatic isentholpic )

from saturated steam table at; ( h= 3615 kJ/kg, P= 5.5 MPa )

Temperature = 581.5 °C

Therefore the final temperature of the steam 581.5 °C

8 0

3 years ago

If a steel cable is rated to take 800-lb and the steel has a yield strength of 90,000psi, what is the diameter of the cable?

goldfiish [28.3K]

Answer:

d = 2.69 mm

Explanation:

Assuming the cable is rated with a factor of safety of 1.

The stress on the cable is:

σ = P/A

Where

σ = normal stress

P: load

A: cross section

The section area of a circle is:

A = π/4 * d^2

Then:

σ = 4*P / (π*d^2)

Rearranging:

d^2 = 4*P / (π*σ)

$d = \sqrt{4*P / (\pi*\sigma)}$

Replacing:

$d = \sqrt{4*800 / (\pi*\90000)} = 0.106 inches$

0.106 inches = 2.69 mm

5 0

3 years ago

An immersion heater has a resistance of 50Ω and carries a current of 2.5A current. What will be the final temperature of 500 g o

Lorico [155]

Answer:

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An immersion heater has a resistance of 50Ω and carries a ...brainly.com › Engineering › High School

An immersion heater has a resistance of 50Ω and carries a current of 2.5A current. ... What will be the final temperature of 500 g of water that is initially at 20ºC after 3 minutes if Does the water absorb all the heat given off by the heater? Does ...

Explanation:

Search Results

Web results

An immersion heater has a resistance of 50Ω and carries a ...brainly.com › Engineering › High School

An immersion heater has a resistance of 50Ω and carries a current of 2.5A current. ... What will be the final temperature of 500 g of water that is initially at 20ºC after 3 minutes if Does the water absorb all the heat given off by the heater? Does ...

8 0

3 years ago

g The parameters of a certain transmission line operating at 휔휔=6 ×108 [rad/s] are 퐿퐿=0.35 [휇휇H/m], 퐶퐶=75 [pF/m], 퐺퐺=75 [휇휇S/m],

yKpoI14uk [10]

Explanation:

$\begin{aligned}\gamma &=\sqrt{Z Y}=\sqrt{(R+j \omega L)(G+j \omega C)} \\&-\sqrt{|17|} j\left(6 \times 10^{8}\right)\left(0.35 \times 10^{-6}\right)|| 75 \times 10^{-6}\left|j\left(6 \times 10^{8}\right)\left(40 \times 10^{-12}\right)\right| \\&=0.094+j 2.25 \mathrm{m}^{-1}-\alpha+j \beta\end{aligned}$

Therefore,

$-\alpha-0.094 \mathrm{Np} / \mathrm{m} . \quad 3-2.25 \mathrm{rad} / \mathrm{m}, \text { and } \lambda-2 \pi / \beta-\underline{2.79} \mathrm{m}$

$Z_{0}-\sqrt{\frac{Z}{Y}}-\sqrt{\frac{R+j \omega L}{G+j \omega C}}-\sqrt{\frac{17+j 2.1 \times 10^{2}}{75 \times 10^{-6}+j 2.4 \times 10^{-2}}}-\frac{93.6-j 3.64 \Omega}{4}$

5 0

3 years ago

Why do giant stars become planetary nebulas while supergiant stars become supernovas when their nuclear fusion slows and is over

sashaice [31]

The reason why giant stars become planetary nebulas is Supergiant stars do not have enough mass to generate the gravity necessary to cause a planetary nebula.

<h3>Why do giant stars become planetary nebulae?</h3>

A planetary nebula is known to be formed or created by a dying star. A red giant is known to be unstable and thus emit pulses of gas that is said to form a sphere around the dying star and thus they are said to be ionized by the ultraviolet radiation that the star is known to releases.

Learn more about giant stars from

brainly.com/question/27111741

#SPJ1

3 0

2 years ago