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Semenov [28]
3 years ago
10

A grindstone increases in angular speed from 4.00 rad/s to 12.00 rad/s in 4.00 s. Through what angle does it turn during that ti

me if the angular acceleration is constant?
a. 8.00 rad
b. 12.00 rad
c. 16.0 rad
d. 32.0 rad
Physics
1 answer:
Sophie [7]3 years ago
4 0

Answer:

d. 32.0 rad

Explanation:

The angular speed, denoted by ω can be calculated thus;

ω = θ /t

Where;

ω = angular speed in radians/sec

θ = angle in radians

t = time in seconds

∆ω = final ω - initial ω

ω = 12.00 rad/s - 4.00 rad/s

ω = 8.00 rad/s

Hence, using ω = θ/t

8.00 = θ/4

θ = 32.00rad

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What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a p
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The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

The given parameters;

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The vertical pressure of the water is calculated as follows;

P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\

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The vertical height of the 13 ft floor = 10  ft

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and we know that force:

F=m\times g

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