Question

A grindstone increases in angular speed from 4.00 rad/s to 12.00 rad/s in 4.00 s. Through what angle does it turn during that time if the angular acceleration is constant?
a. 8.00 rad
b. 12.00 rad
c. 16.0 rad
d. 32.0 rad

Answer 1

Answer:

d. 32.0 rad

Explanation:

The angular speed, denoted by ω can be calculated thus;

ω = θ /t

Where;

ω = angular speed in radians/sec

θ = angle in radians

t = time in seconds

∆ω = final ω - initial ω

ω = 12.00 rad/s - 4.00 rad/s

ω = 8.00 rad/s

Hence, using ω = θ/t

8.00 = θ/4

θ = 32.00rad