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Alenkasestr [34]
3 years ago
8

From the data presented in the report sheet, you can deduce that the stoichiometric coefficient for oxygen is _______.

Chemistry
1 answer:
tatuchka [14]3 years ago
3 0

Answer: The stoichiometric coefficient for oxygen is \frac{1}{2}.

Explanation:

A number present on the front of an atom, ion or molecule in a chemical reaction equation is called a stoichiometric coefficient.

For example, H_{2}O(l) \rightarrow H_{2}(g) + \frac{1}{2}O_{2}(g)

Here, the stoichiometric coefficient for H_{2}O(l) is 1, for H_{2}(g) is 1 and for O_{2} is \frac{1}{2}.

Thus, we can conclude that the stoichiometric coefficient for oxygen is \frac{1}{2}.

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Determine the equilibrium constant, Keq, at 25°C for the reaction
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Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

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The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

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E^ocell= (-1.07+0.53)V\\=-0.54V

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Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

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