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LenaWriter [7]
3 years ago
9

Can someone please help me with this

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

First balance the equation: you get 3Fe + 4H2O = Fe3O4 +4H2O

Then set up the equations according to the spidey map below.

x 10^25 molec. H2O/ 1 x x x

Multiply the top all together, then divide by the whole bottom half.

Answer: 154.4 g H2

136 g Fe /1 x \frac{1molFe}{55.85 g Fe} x \frac{1molFe3O4}{3molFe} x \frac{6.02(10x^{23}) molec. Fe3O4 }{1molFe3O4}

Multiply the top all together, then divide by the whole bottom half.

Answer: 4.95 x 10^20 Formula units (fu) Fe3O4

8.25 x 10^23 molec. Fe/ 1 x \frac{1molFe}{6.02(10^{23})molec.Fe} x \frac{4molH2}{3molFe}

Multiply the top all together, then divide by the whole bottom half.

Answer: 1.83 mol H2

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4. How many moles of gold (Au) are in a pure gold nugget having a mass of 25.0 grams.
ikadub [295]
<h3>Answer:</h3>

0.127 mol Au

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 25.0 g Au

[Solve] moles Au

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of Au - 196.97 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 25.0 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})
  2. [DA] Multiply/Divide [Cancel out units:                                                          \displaystyle 0.126923 \ mol \ Au

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.126923 mol Au ≈ 0.127 mol Au

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3 years ago
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A student is instructed to make 1 L of a 2.0 M solution of CaCl2 using dry salt. How should he do this?
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<span>6. Then top up to mark of the volumetric flask carefully. 
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