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gtnhenbr [62]
3 years ago
9

How is a physical change different from a chemical change

Physics
2 answers:
lorasvet [3.4K]3 years ago
7 0
There's a few differences. In a physical change the actual substance doesn't change, where in a chemical change with chemical reaction, a new substance is formed. Physical change can be reversed, and chemical change can't.
storchak [24]3 years ago
4 0
There are several differences between a physical and chemical change in matter or substances. A physical change in a substance doesn't change what the substance is. In a chemical change where there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.
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296/km from city A, the vehicles will pass each other.
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3 years ago
A sample of a monatomic ideal gas initially at temperature T, undergoes a process during which the pressure of the gas triples a
Allisa [31]

Answer:

B) 8 T.

Explanation:

For an ideal gas , the gas law that it follow is as follows

P₁V₁ / T₁ = P₂ V₂ /T₂

This law is followed by all the gases whether mono atomic or diatomic.

In this case following information are given

P₂ / P₁ = 3

V₂ / V₁ = 3

T₁ = T

T₂ = ?

From the gas law formula given , we have

T_2 =\frac{P_2\times V_2\times T_1}{P_1\times V_1}

V_2 = \frac{P_2}{P_1} \times\frac{V_2}{V_1}\times T

= 3 X 3 T

= 9 T

Change in temperature = 9T - T = 8 T.

7 0
3 years ago
To balance a chemical equation we use______. <br> -coefficients <br> -subscripts
Vitek1552 [10]

Answer:

Coefficients

Explanation:

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3 0
3 years ago
Two sound waves, from two different sources with the same frequency, 540 Hz, travel in the same direction at 330 m s . The sourc
oee [108]

Answer:

The value is \Delta  \phi   =   4.12 \ rad

Explanation:

From the question we are told that

    The frequency of each sound is  f_1 = f_2 = f =  540 \  Hz

      The speed of the sounds is  v = 330 \  m/s

       The  distance of the first source from the point considered is  a = 4.40 \  m

        The distance of the second source from the point considered is  b  = 4.00  \  m

Generally the phase angle made by the first sound wave at the considered point is mathematically represented as

           \phi_a =  2 \pi [\frac{a}{\lambda}  + ft]

Generally the phase angle made by the first sound wave at the considered point is mathematically represented as

           \phi_b =  2 \pi [\frac{b}{\lambda}  + ft]          

Here b is the distance o f the first wave from the considered point  

Gnerally the phase diffencence is mathematically represented as  

           \Delta \phi= \phi_a - \phi_b  =  2 \pi [\frac{ a}{\lambda}  + ft ] - 2 \pi [\frac{b}{\lambda}  + ft ]      

=>      \Delta  \phi   =   \frac{2\pi [ a - b]}{ \lambda }

Gnerally the wavelength is mathematically represented as

        \lambda  =  \frac{v}{f}

=>     \lambda  =  \frac{330}{540}

=>     \lambda  =  0.611 \ m

=>    \Delta  \phi   =   \frac{2* 3.142 [ 4.40 - 4.0 ]}{  0.611  }

=>    \Delta  \phi   =   4.12 \ rad

     

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