All categories

2 years ago

Help me out please!!??!

Mathematics

2 answers:

pochemuha2 years ago

6 0

The awnser is 18 degrees

liberstina [14]2 years ago

5 0

Answer:

10°is the answer

<2=180-100=80°

<3=90-<2=90-80=10°

You might be interested in

9/10 + 9/100 + 9/1000 + 9/10000 + … =

Korvikt [17]

Answer: $0.9999$

Step-by-step explanation:

4 0

2 years ago

Two drivers are exploring the bottom of a trench in the Pacific Ocean. Dominic is at 175 feet below the surface of the ocean and

mestny [16]

$\huge\boxed{\text{Dominic}}$

In this problem, $0$ represents the sea level. Since Dominic is $175$ feet below the surface (sea level), his current location is at $-175$ feet.

The same concept can be applied to Karen, who is at $-138$ feet.

We need to find who is lower, or farther below $0$ . This means the answer is $\boxed{\text{Dominic}}$ .

7 0

3 years ago

A movie theater has seats arranged in 25 rows with 30 seats in each row. How many seats are in the theater?

monitta

Answer: 750

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

How do you do this problem?

Burka [1]

Let area of triangle AEC = x

Area of triangle BAC = 1/2 * 15 * 12 = 90

Area of triangle DCA = 1/2 * 15 * 6 = 45

90 = p + x and

45 = q + x Subtracting the 2 equations:-

90 - 45 = p - q

Answer p - q = 45

7 0

2 years ago

Read 2 more answers

Find the sum of ∠BCD and ∠SBT in terms of x.

AleksAgata [21]

$Let's\ \angle TCB=y^o\\\\\angle SBT\ is\ the\ exterior\ angle\ of\ \Delta TCB,\ therefore\ |\angle SBT|=x^o+y^o.\\\\|\angle\ BCD|\ +\ y^o=180^o-angles\ on\ one\ side\ of\ a\ straight\ line\\\\|\angle BCD|=180^o-y^o\\\\therefor\\\\\angle SBT+\angle BCD=x^o+y^o+180^o-y^o=x^o+180^o\\\\\boxed{Answer:\angle SBT+\angle BCD=x^o+180^o}$

4 0

2 years ago

Read 2 more answers