An archer pulls her bowstring back 0.396 m by exerting a force that increases uniformly from zero to 237 N. (a) What is the equi
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Answer:
The transverse component of acceleration is 26.32 where as radial the component of acceleration is 8.77
Explanation:
As per the given data
u=π/4 rad
ω=u'=2 rad/s
α=u''=4 rad/s
So the transverse component of acceleration are given as
Here
So
The transverse component of acceleration is 26.32
The radial component is given as
Here
So
The radial component of acceleration is 8.77
The angle of the pendulum with the vertical is
Explanation:
As the train decelerates, the bob of the pendulum will feel a force given by
where
m = 0.55 kg is the mass of the bob
is the magnitude of the acceleration
In the horizontal direction.
The pendulum will be inclined at an angle from the vertical, so it will be in equilibrium, and therefore the horizontal component of the tension in the string must be equal to the net force F of the previous equation:
(1)
where T is the tension in the string.
We also know that the bob is in equilibrium along the vertical direction: so the vertical component of the tension must be equal to the weight of the bob,
(2)
where is the acceleration of gravity.
Dividing eq.(1) by eq(2), we get:
And therefore, we find the angle:
Learn more about forces and acceleration:
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