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finlep [7]
4 years ago
5

An archer pulls her bowstring back 0.396 m by exerting a force that increases uniformly from zero to 237 N. (a) What is the equi

valent spring constant of the bow? 598.48 Correct: Your answer is correct. N/m (b) How much work does the archer do on the string in drawing the bow?
Physics
1 answer:
tatyana61 [14]4 years ago
6 0

Answer:

(a) The equivalent spring constant is 598.485 N/m

(b) The work done is 46.926 J

Explanation:

From Hooke's law of elasticity

K (spring constant) = F/e

F is the range of force exerted = 237 - 0 = 237 N

e is the extension of bowstring = 0.396 m

K = F/e = 237/0.396 = 598.485 N/m

Work done = 1/2 Fe = 1/2 × 237 × 0.396 = 46.926 J

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inessss [21]

Explanation:

Let yellow ball be m1 = 0.5kg with u1 = 8 m/s and blue ball be m2 = 0.25 kg with u2 = - 4 m /s respectively.

After collision, blue ball travels 12 m/s.

<u>Using conservation of Linear Momentum</u> :

m1u1 + m2u2 = m1v1 + m2v2

0.5* 8 + 0.25 * - 4 = 0.5 * v1 + 0.25 * 12

v1 = 0 m/sec i.e. <u>Yellow ball comes to rest</u>.

3 0
3 years ago
Suppose you had 10 identical molecules enclosed by a box. At a given instant, one molecule has an energy of 100 Joules, and the
boyakko [2]

Answer:

A)   K_average = 1/20 m v², B) low entropy , C) entropy increases.

Explanation:

A) The kinetic energy of each molecule

         K = ½ m v²

The average kinetic energy is the sum of each kinetic energy among the number of them

        K_average = (½ m v² + 0 + 0 +) 10

        K_average = 1/20 m v²

B) Entropy is the sum of the states of each molecule, in this configuration there are only two states one with energy and the other with zero energy, so it is a system with low entropy.

       S = k ln W

  Where S is the entropy, k the Bolztmann constant, W the amount of state present in the system in this case is 2

C) Let's start by analyzing the entropy, as time goes by the molecule that is moving collides with the other molecules and transfers them some energy, so the other molecules move to a different state, after a little In time all the molecules will have the same energy, each one in a different state or volume, so the number of possible state increases to 10, so the entropy increases.

Now let's analyze what happens with the energy of the system, for this case we have two possibilities

- The system is isolated, therefore as it cannot exchange energy with the environment, the total energy remains constant even when the energy of each molecule can fluctuate.

- If the system is not isolated, it can exchange energy with the environment, therefore the total energy changes, depending on the difference in energy between the molecules and the environment

4 0
4 years ago
what do you understand by gravitational potential energy? what is the increase in the gravitational potential energy of a 20 kg
enyata [817]

Answer:

  • energy possessed by any object due to its position in gravitational field
  • it is given by the equation P.E.= mgh where m = mass ,g= gravitational force of earth ( 9.8m/s^2) and h= hight of the object
  • there for for above problem m = 20kg , h= 10 m and g= (9.8m/s^2)
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Explanation:

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5 0
3 years ago
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The drag force, fd, imposed by the surrounding air on a vehicle moving with velocity v is given by fd = cdaρv 2/2 where cd is a
kiruha [24]

Answer: 191 N

Explanation:

Given that,

Velocity v = 80 km/hr

Area a = 2.3\ m^{2}

Air density \rho = 1.2\ kg/m^{3}

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F_{d} = 190.8 N

F_{d} = 191 N

Hence, the drag force is 191 N.








7 0
3 years ago
Two identical metallic sphere having unequal opposite charges are are placed
velikii [3]

Answer:

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After they come in contact, the charges are rearranged such that they acquire same charge.

let us say that charge on each of them is Q.

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F = kQ2 / r2

0.025 = (9×109 x Q2) / 0.92

Q2 = 0.025 x 0.92 / 9×109

Q = 1.5 x 10-6 C

Explanation:

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3 years ago
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