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Aneli [31]
3 years ago
12

Describe the process of organic vegetable production.​

Chemistry
1 answer:
Julli [10]3 years ago
4 0

Explanation:

The basic concepts behind Organic farming are: ... Control of pests, diseases, and weeds is achieved largely by the development of an ecological balance within the system and by the use of bio-pesticides and various cultural techniques such as crop rotation, mixed cropping, and cultivation.

hope it helps follow me to say thanks

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Which distance measures 5 units? the distance between points W and X the distance between points X and Y the distance between po
MA_775_DIABLO [31]

Answer:

Its Option A if you are on ed.

Explanation:

8 0
4 years ago
Read 2 more answers
How many grams of nicl2∙6h2o will be used to prepare a 0. 0350 m, 500. 0 ml of nicl2 solution?
marin [14]

The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g

<h3>What is molarity? </h3>

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of NiCl₂•6HO₂</h3>
  • Molarity = 0.035 M
  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Mole of NiCl₂•6HO₂ =?

Mole = Molarity × Volume

Mole of NiCl₂•6HO₂ = 0.035 × 0.5

Mole of NiCl₂•6HO₂ = 0.0175 mole

<h3>How to determine the mass of NiCl₂•6HO₂</h3>
  • Mole of NiCl₂•6HO₂ = 0.0175 mole
  • Molar mass of NiCl₂•6HO₂ = 238 g/mol
  • Mass of NiCl₂•6HO₂ =?

Mass = mole × molar mass

Mass of NiCl₂•6HO₂ = 0.0175 × 238

Mass of NiCl₂•6HO₂ = 4.165 g

Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution

Learn more about molarity:

brainly.com/question/15370276

3 0
3 years ago
When matter changes into new of different substance
IgorLugansk [536]
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5 0
4 years ago
Carbon-14 emits beta radiation and decays with a half life of 5730 years. Assume you start with 2.5x10^15 grams of Carbon-14, ho
saveliy_v [14]

The amount remaining at the end of 5 half-lives is 7.81×10¹³ g

From the question given above, the following data were obtained:

  • Half-life (t½) = 5730 years
  • Original amount (N₀) = 2.5×10¹⁵ g
  • Number of half-lives (n) = 5
  • Amount remaining (N) =?

The amount remaining can be obtained as follow:

N = 1/2ⁿ × N₀

N = 1/2⁵ × 2.5×10¹⁵

N = 1/32 × 2.5×10¹⁵

N = 0.03125 × 2.5×10¹⁵

N = 7.81×10¹³ g

Therefore, the amount remaining after 5 half-lives is 7.81×10¹³ g

Learn more about half-life: brainly.com/question/25783920

3 0
2 years ago
6 NaOH + 2 Al --&gt; 2 Na3AlO3 + 3 H2 If you start with 258 g of Al, how many moles of Na3AlO3 can you make?
tatyana61 [14]

Solution :

Assuming all Al will be consumed in the reaction.

From the given equation, 2 mole of Al produce 2 mole of Na_3AlO_3.

So, 1 mole of Al produce 1 mole of  Na_3AlO_3.     .....statement 1)

Number of moles of Al in 258 gram of Al.

n = \dfrac{mass}{molar\ mass}\\\\n = \dfrac{258}{27}\ moles\\\\n = 9.556 \ moles

Therefore, from statement 1) number of moles of Na_3AlO_3 produced is also 9.556 moles.

7 0
3 years ago
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