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charle [14.2K]
3 years ago
7

When matter changes into new of different substance

Chemistry
1 answer:
IgorLugansk [536]3 years ago
5 0
I don’t know jsnshanhs shznjs
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Can someone please help me with the gizmo please<br><br> message me if your willing to help :(
77julia77 [94]

Answer:

airing Your GizmoWatch to the GizmoHub App 10. Register ... NOTE: If any component is missing, please contact the store ... Gizmo Buddies can text the GizmoWatch ... Tap Kids to access your child's full profile. If you have more than one child, swipe left or right to ... portable devices with LCD panels may be used to help.

Explanation:

4 0
3 years ago
What is the mass of 3.75 moles of NaCl
insens350 [35]
Mass of salt is equal to 218.8125 grams.

6 0
3 years ago
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If the energy of photon emitted from the hydrogen atom is 4.09 x 10-19 J, what is
Aliun [14]

Answer:

486 nm

Explanation:

From the question given above, the following data were obtained:

Energy (E) = 4.09×10¯¹⁹ J

Wavelength (λ) =?

Next, we shall determine the frequency of the photon. This can be obtained as follow:

Energy (E) = 4.09×10¯¹⁹ J

Planck's constant (h) = 6.63×10¯³⁴ Js

Frequency (f) =?

E = hf

4.09×10¯¹⁹ = 6.63×10¯³⁴ × f

Divide both side by 6.63×10¯³⁴

f = 4.09×10¯¹⁹ / 6.63×10¯³⁴

f = 6.17×10¹⁴ Hz

Next, we shall determine the wavelength of the photon. This can be obtained as follow:

Frequency (f) = 6.17×10¹⁴ Hz

Velocity of photon (v) = 3×10⁸ m/s

Wavelength (λ) =?

v = λf

3×10⁸ = λ × 6.17×10¹⁴

Divide both side by 6.17×10¹⁴

λ = 3×10⁸ / 6.17×10¹⁴

λ = 4.86×10¯⁷ m

Finally, we shall convert 4.86×10¯⁷ m to nm. This can be obtained as follow:

1 m = 1×10⁹ nm

Therefore,

4.86×10¯⁷ m = 4.86×10¯⁷ m × 1×10⁹ nm / 1 m

4.86×10¯⁷ m = 486 nm

Therefore, the wavelength of the photon is 486 nm

7 0
3 years ago
Can i has help?
Lerok [7]

Answer:

water, lead, and wood

Explanation:

All are correct on Edg 2020

3 0
3 years ago
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Two common methods to generate an aldehyde is by oxidation of an alcohol and through ozonolysis.
kotykmax [81]

Answer:

<u>a</u><u>.</u><u> </u><u>True</u><u>.</u>

Explanation:

Only primary and secondary alcohols can oxidise to give an aldehyde. But a weak oxidizing agent must be used to prevent formation of a carboxylic acid or ketone.

weak oxidizing agents: Chromyl chloride, silver/oxygen/500°C

take an example of <u>e</u><u>t</u><u>h</u><u>a</u><u>n</u><u>o</u><u>l</u><u>:</u>

<u>{ \bf{CH _{3} CH_{2}OH \:  \:  \frac{Ag/O_{2} }{500 \degree C}  >  \:  \:CH _{3} CHO}}</u>

<u>{ \sf{CH _{3} CHO \:  \: is \: ethanal}}</u>

<u>B</u><u>y</u><u> </u><u>o</u><u>z</u><u>o</u><u>n</u><u>o</u><u>l</u><u>y</u><u>s</u><u>i</u><u>s</u><u>:</u>

Here, reactants are Ozone gas, Carbon tetrachloride at a temperature (<20°C), ethanoic acid, zinc and water.

take an example of propanol:

if it undergoes ozonolysis, it gives ethanal and methanal.

5 0
3 years ago
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