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3 years ago

Describe the motion of an automobile on an east-west

Physics

1 answer:

Tanya [424]3 years ago

4 0

Answer:

1. The automobile is traveling due east and is speeding up.

2. The car is traveling due east and is is slowing down.

3. The automobile is traveling due east at a constant speed.

4. The car is traveling due west and is slowing down.

5. The automobile is traveling due west and is speeding up.

6. The automobile is traveling due west at a constant speed.

7. The automobile is accelerating due east from rest.

8. The automobile is accelerating due west from rest.

Explanation:

The key to understanding this is:

When the acceleration and initial velocity of the automobile have the same sign (positive or negative) then the automobile is speeding up. Explained further, if acceleration and the initial velocity are both positive or they are both negative the automobile is speeding up but whenever they have opposite signs (that is acceleration is positive and initial velocity is negative or vice versa) the automobile is slowing down. When the acceleration is zero the automobile is maintaining a unform motion at a constant speed (the speed is not changing with time). The + or - sign indicates the direction of travel. In this case east is + and west is -. It is my pleasure answering this question. I hope you find it helpful. Thank you.

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A physics student drops a rock from a 55m cliff. How long does it take to hit the ground?

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Answer: 9.9 seconds

Explanation:

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If someone looks far enough into space, they should be able to see the beginning of the universe true of false

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3 years ago

The second-order decomposition of hi has a rate constant of 1.80 x 10−3 m−1 s−1. How much hi remains after 45.6 s if the initial

zlopas [31]

Answer:

2.9 M

Explanation:

The concentration-time equation for a second order reaction is:

1/[A] = kt + 1/[A°]

Where,

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1/[A] = (1.80 x 10^-3) * (45.6) + 1/3.81

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A raccoon falls out of a tree from a height of 1.2. Which equation can you use to calculate the time it takes for the raccoon to

Inga [223]

Answer:

$t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2 \cdot 1.2 m}{9.81 m/s^2}}=0.50 s$

Explanation:

The equation that we can use to calculate the time it takes for the raccoon to fall to the ground is:

$t=\frac{2S}{g}$

where S=1.2 m is the height of the tree and g=9.81 m/s^2 is the acceleration due to gravity. This equation is derived from the equation of the distance in a uniformly accelerated motion, which is given by

$S=S_0 + v_0 t + \frac{1}{2}at^2$

where S0 is the initial position, v0 is the initial velocity and t the time. In this problem, we can put S0=0 (we can take the initial position as the initial position of the raccoon) and v0=0 (the raccoon starts from rest), so the equation becomes

$S=\frac{1}{2}at^2$

and since the motion is a free fall, the acceleration is equal to the acceleration of gravity, so a=g:

$S=\frac{1}{2}gt^2$

And by re-arranging it, we find

$t=\sqrt{\frac{2S}{g}}$

By substituting numbers, we find

$t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2 \cdot 1.2 m}{9.81 m/s^2}}=0.50 s$

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