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3 years ago

THE FIRST TO ANSWER WILL GET BRAINLIEST!!!! Compare and contrast the three main layers of the earth.

Physics

1 answer:

Viefleur [7K]3 years ago

4 0

Answer:

The first layer is the crust a very thin layer compared to any other

the second layer is the mantal there is 2 parts to the matal there is a solid mental and a hard mental

the last part is the core the most dense part of earth

Explanation:

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The table shows the percentage of carbon dioxide in the Earth’s atmosphere in the years 1800 and 2013. Calculate the difference

Natalka [10]

The difference in the mass of carbon dioxide in 500 kg of air in 2013 compared to 1800 is 0.06 Kg

<h3>Data obtained from the question</h3>

Year 1800 percent = 0.028%
Year 2013 percent = 0.040%
Mass of air = 500 Kg
Difference =?

<h3>How to determine the mass of CO₂ in 500 Kg in year 1800</h3>

Year 1800 percent = 0.028%
Mass of air = 500 Kg
Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.028% × 500

Mass of CO₂ = 0.14 Kg

<h3>How to determine the mass of CO₂ in 500 Kg in year 2013</h3>

Year 1800 percent = 0.040%
Mass of air = 500 Kg
Mass of CO₂ =?

Mass = percent × mass of air

Mass of CO₂ = 0.040% × 500

Mass of CO₂ = 0.2 Kg

<h3>How to determine the difference</h3>

Mass of CO₂ in year 1800 = 0.14 Kg
Mass of CO₂ in year 2013 = 0.2 Kg
Difference =?

Difference = mass in 2013 - mass in 1800

Difference = 0.2 - 0.14

Difference = 0.06 Kg

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7 0

2 years ago

What advantage does a telescope in space have over one located on the ground.

klio [65]

A telescope in space can focus on any object while a telescope on the ground cannot focus on the object it is on

7 0

4 years ago

A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine

Tju [1.3M]

Answer:

$_T}=24.57Nm$

ω = 0.0347 rad/s²

a ≅ 1.07 m/s²

Explanation:

Given that:

mass of the model airplane = 0.741 kg

radius of the wire = 30.9 m

Force = 0.795 N

The torque produced by the net thrust about the center of the circle can be calculated as:

$_T } = Fr$

where;

F represent the magnitude of the thrust

r represent the radius of the wire

Since we have our parameters in set, the next thing to do is to replace it into the above formula;

So;

$_T}=(0.795)*(30.9)$

$_T}=24.57Nm$

(b)

Find the angular acceleration of the airplane when it is in level flight rad/s²

$_T}=I \omega$

where;

I = moment of inertia

ω = angular acceleration

The moment of inertia (I) can also be illustrated as:

$I = mr^2$

I = ( 0.741) × (30.9)²

I = 0.741 × 954.81

I = 707.51 Kg.m²

$_T}=I \omega$

Making angular acceleration the subject of the formula; we have;

$\omega = \frac{_T}{I}$

ω = $\frac{24.57}{707.51}$

ω = 0.0347 rad/s²

(c)

Find the linear acceleration of the airplane tangent to its flight path.m/s²

the linear acceleration (a) can be given as:

a = ωr

a = 0.0347 × 30.9

a = 1.07223 m/s²

a ≅ 1.07 m/s²

5 0

3 years ago

Write the dimensional formula of<br>presor and gravitation constant<br>

deff fn [24]

Or, G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2]. Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.

8 0

3 years ago

Using kinetic energy to determine height

Anon25 [30]

For the gravitational force the formula<span> is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s</span>2<span> at the surface of the earth) and h is the </span>height<span> in meters. Notice that gravitational potential </span>energy<span> has the same units as </span>kinetic energy, kg m2<span> / s</span>2<span>.

HOPE THIS HELPS</span>

7 0

3 years ago