Write the net ionic equation for the reaction between hydrochloric acid and potassium cyanide. Do not include states such as (aq
1 answer:
Answer: , product favoured
Explanation:
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.
When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.
The complete ionic equation will be:
The net ionic equation will not contain spectator ions which are and
:
The reaction is product favoured.
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Answer:
a.36 g of water is produced.
b.64 g of is consumed.
Explanation:
The reaction is ⇒
a.
Given,
Weight of reacted = 4g
Weight of 1 mole of = 2
1 = 2g
Therefore no. of moles of reacted =
= 2 moles;
Also given,
Weight of reacted = 32 g
Weight of 1 mole of = 2
16 = 32 g
Therefore no. of moles of reacted =
= 1
We know that 2 moles of Hydrogen reacts with 1 mole of Oxygen to give 2 moles of water,
As we took 2 moles of Hydrogen and 1 mole of Oxygen,
Directly,from the equation we can tell 2moles of water will be produced.
Therefore no. of moles of produced = 2
Weight of 1 mole of water = = 18
Therefore weight of produced =
= 36gm
b.
Given ,
72 g of is produced.
So,
no. of moles of produced =
= 4 moles
From equation For every 2 moles of water formed , 1 mole of oxygen must be required.
So for producing 4 moles of water,
No. of moles of Oxygen required = 2 moles.
Therefore weight of reacted =
= 64 g
Method 2:
Given,
8 g of has reacted.
So,
no. of moles of reacted =
= 4 moles.
From equation , we know that For every 2 moles of reacted,1 mole of
will react.
Therefore,
No. of moles of that reacts with 4 moles of
=
= 2 moles
Therefore the weight of reacted =
= 64 g