H2O2(I)
C6H6(O)
CO2(I)
C2H6(O)
HNO3(I)
Answer:
The 1st and 2nd ones on the top
Explanation:
Hope this helps:)
Answer:
0.50 M
Explanation:
Given data
- Mass of sodium sulfate (solute): 7.1 g
- Volume of solution: 100 mL
Step 1: Calculate the moles of the solute
The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

Step 2: Convert the volume of solution to liters
We will use the relation 1 L = 1000 mL.

Step 3: Calculate the molarity of the solution

Answer:
carbon, hydrogen, and oxygen atoms
Explanation:
brainliest pls
The given concentration of boric acid = 0.0500 M
Required volume of the solution = 2 L
Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.
Calculating the moles of 0.0500 M boric acid present in 2 L solution:

Converting moles of boric acid to mass:

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.