Answer:
0.053 M is the concentration of X after 196 seconds.
Explanation:
Initial concentration of the X = ![[A_o]=1.0 M](https://tex.z-dn.net/?f=%5BA_o%5D%3D1.0%20M)
Time taken by the sample, t = 196 s
Final concentration of the X after t = [A] =?
Rate constant of the reaction = k = 
Formula used :
![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)
where,
Now put all the given values in this formula, we get
![[A]=[1.0M]\times e^{-1.50\times 10^{-2} s^{-1}\times 196 s}](https://tex.z-dn.net/?f=%5BA%5D%3D%5B1.0M%5D%5Ctimes%20e%5E%7B-1.50%5Ctimes%2010%5E%7B-2%7D%20s%5E%7B-1%7D%5Ctimes%20196%20s%7D)
![[A]=0.053 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.053%20M)
0.053 M is the concentration of X after 196 seconds.
Answer:
The answer to your question is pH = 5
Explanation:
Data
[H⁺] = 1 x 10⁻⁵
pH = ?
pH is a measure of the hydrogen concentration. It measures the acidity or alkalinity. The range of pH goes from 0 to 14. The pH for an acid is from 0 to 6.9, for a neutral solution is 7.0 and for an alkali is from 7.1 to 14.
Formula
pH = -log [H⁺]
-Substitution
pH = -log [1 x 10⁻⁵]
-Simplification
pH = - (-5)
-Result
pH = 5
SO₂ is made from 1 S atom and 2 O atoms.
SO₂ → S + 2O
The stoichiometric ratio between SO₂ and O atom is 1 : 2.
Hence,
moles of SO₂ = (moles of O atoms) / 2
= 3.8 mol / 2
= 1.9 mol
Hence, moles of SO₂ is 1.9 when there are 3.8 moles of O atoms.
Answer:
1. The empirical formula => C₆H₁₀OS₂
2. Molecular formula => C₃₆H₆₀O₆S₁₂
Explanation:
1. Determination of the empirical formula.
Carbon (C) = 2.96 g
Hydrogen (H) = 0.414 g
Oxygen (O) = 0.675 g
Sulphur (S) = 2.96 g
Divide by their molar mass
C = 2.96 / 12 = 0.247
H = 0.414 / 1 = 0.414
O = 0.675 / 16 = 0.042
S = 2.96 / 32 = 0.0925
Divide by the smallest
C = 0.247 / 0.042 = 6
H = 0.414 / 0.042 = 10
O = 0.042 / 0.042 = 1
S = 0.0925 /0.042 = 2
Therefore, the empirical formula is
C₆H₁₀OS₂
2. Determination of the molecular formula.
Molar mass of compound = 972 g/mol
Empirical formula => C₆H₁₀OS₂
Molecular formula =>?
Molecular formula = [C₆H₁₀OS₂]ₙ
Molecular formula = molar mass of compound
Thus,
[C₆H₁₀OS₂]ₙ = 972
[(12×6) + (10×1) + 16 + (32×2)]n = 972
[72 + 10 + 16 + 64]n = 32
162n = 972
Divide both side by 162
n = 972 / 162
n = 6
Molecular formula = [C₆H₁₀OS₂]ₙ
Molecular formula = [C₆H₁₀OS₂]₆
Molecular formula = C₃₆H₆₀O₆S₁₂
Answer:
545.2
Explanation:
To read a beam balance, you need to add together the numbers that each balance reads.
The first beam reads 500.
The second beam reads 40.
The third beam reads 5.2.
500 + 40 + 5.2 = 545.2
The total mass of the rock sample is 545.2.
