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34kurt
3 years ago
11

A car is traveling in a race.The car went from the initial velocity of 35 to the final velocity of 65 in 5 seconds what is the a

cceleration
Physics
1 answer:
Ann [662]3 years ago
7 0

Answer:

Acceleration = 6m/s²

Explanation:

<u>Given the following data;</u>

Initial velocity = 35m/s

Final velocity = 65m/s

Time = 5 seconds

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Where,

  • a is acceleration measured in ms^{-2}
  • v and u is final and initial velocity respectively, measured in ms^{-1}
  • t is time measured in seconds.

Substituting into the equation, we have

a = \frac{65 - 35}{5}

a = \frac{30}{5}

<em>Acceleration = 6m/s²</em>

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(eText prob. 4.25 with some values changed) Air enters a diffuser of a jet engine operating at steady state at 2.65 psia, 389◦R,
krek1111 [17]

Answer:

V_2 = 45.44m/s

Explanation:

We have to many data in different system, so we need transform everything to SI, that is

P_1 = 2.65 Psi = 18.271 kPa\\T_1= 389\°R = 216 K\\V_1 = 869ft/s = 264m/s\\T_2 = 450\°R = 250K

When we have all this values in SI apply a Energy Balance Equation,

\dot{Q}_{cv}-\dot{W}_{cv}+\dot{m}[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0

Solving for V_2

V_2 = \sqrt{V_1^2+2(h_1-h_2)}

From the table of gas properties we calculate for T_1 = 216K and T_2 = 250K

h_1 = 209.97+(219.97-209.97)(\frac{216-210}{220-210})

h_1 = 215.97kJ/kg

For T_2;

h_2 = 250.05kJ/kg

Substituting in equation for V_2

V_2 = \sqrt{V_1^2+2(h_1-h_2)}

V_2 = \sqrt{265^2+2(215.97-250.05)*10^3}\\V_2 = 45.44m/s

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3 years ago
To view an interactive solution to a problem that is similar to this one, select Interactive Solution 7.24. A 0.0146-kg bullet i
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Answer:

0.25223 seconds.

Explanation:

m_1 = Mass of bullet = 0.0146 kg

m_2 = Mass of block = 2.55 kg

v = Combined velocity

u_1 = Velocity of bullet = 816 m/s

g = Acceleration due to gravity = 9.81 m/s²

As linear momentum is conserved

m_1u_1 + m_2u_2 =(m_1 + m_2)v

Now u_2=v as the block (with the bullet in it) reverses direction and rises,

m_1u_1 + m_2v =(m_1 + m_2)v\\\Rightarrow m_1u_1=(m_1 + m_2)v-m_2v\\\Rightarrow 0.0146\times 816=(0.0146 + 2.55)v-(-2.55v)\\\Rightarrow 11.9136=2.2646v+2.55v\\\Rightarrow 11.9136=4.8146v\\\Rightarrow v=\frac{11.9136}{4.8146}\\\Rightarrow v=2.47447\ m/s

Equation of motion

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{2.47447-0}{9.81}\\\Rightarrow t=0.25223\ s

The time t is 0.25223 seconds.

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A same-size iron ball and wooden ball are dropped simultaneously from a tower and reach the ground at the same time. The iron ba
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Answer:

momentum of iron ball is greater than wooden ball

Explanation:

when metal ball (iron ball) and wooden drop are drop from same elevation and reaching the ground after same time. at this position the iron ball has greater momentum than wooden ball

we know that momentum is defined as

P=Mv

and we know also that mass of iron ball is greater than mass of wooden ball and they reached on ground at same time  and same distance it mean also velocity will be same for both ball. therefore from above relation we have

Miron*V > Mwood*V i.e.

momentum of iron ball is greater than wooden ball

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