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2 years ago

Help me ASAP !!! Thank youuu

Chemistry

2 answers:

Neporo4naja [7]2 years ago

7 0

Answer:

uhh the first one is the baby plants are gentically simulator to the parent if its wrong im sorry

Explanation:

Marina CMI [18]2 years ago

7 0

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The rate of heat transfer by radiation is best described by which statement?

bogdanovich [222]

requires a medium to propagate

Explanation:

due to radiation z a dispersion of light ray into different multiple

7 0

2 years ago

How many moles of Al2O3 can be formed from 10.0 g of Al?

Nutka1998 [239]

Answer:

n Al= 10/27( mol)- >n Al2O 3 =5/27(mol)

Explanation:

3 0

2 years ago

Calculate the molality, molarity, and mole fraction of FeCl3 in a 29.5 mass % aqueous solution (d = 1.283 g/mL).

faltersainse [42]

Answer:

molality FeCl3= 2.579 molal

molarity FeCl3 = 2.333 M

mol fraction FeCl3 = 0.0444

Explanation:

Step 1: Data given

Mass % = 29.5 %

Density = 1.283 g/mL

Molar mass FeCl3 = 162.2 g/mol

Step 2: Calculate mass solution

Suppose we have 1L = 1000 mL solution

Mass solution = 1.283 g/mL * 1000 mL = 1283 grams

Step 3: Calculate mass FeCl3

Mass FeCl3 = 0.295 * 1283 grams

Mass FeCl3 = 378.485 grams

Step 4: Calculate mass of water

Mass water = 1283 - 378.485 = 904.515 grams

Step 5: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 378.485 grams / 162.2 g/mol

Moles FeCl3 = 2.333 moles

Step 6: Calculate moles H2O

Moles H2O = 904.515 grams / 18.02 g/mol

Moles H2O = 50.195 moles

Step 7: Mol fraction FeCl3

Mol fraction FeCl3 = 2.333 / (50.195+2.333)

Mol fraction FeCl3 = 0.0444

Step 8: Calculate molality

Molality = moles FeCl3 / mass H2O

Molality = 2.333 moles / 0.904515 kg

Molality = 2.579 molal

Step 9: Calculate molarity

Molarity = moles / volume

Molarity FeCl3 = 2.333 moles / 1 L

Molarity FeCl3 = 2.333 M

8 0

3 years ago

the element Potassium is found in the fourth. Of the periodic table what does that tell you about an atom of potassium

alexira [117]

It tells you how many atoms it has, how many protons it contains and the number of electrons.

6 0

3 years ago

What mass of zinc is needed to react with 23.1 g of phrosphoric acid according tot he equation?

Hitman42 [59]

Complete Question:

what mass of zinc is needed to react with 23.1 g of phosphoric acid according tot he equation?

3 Zn + 2 H₃PO₄ = 3 H₂ + Zn₃(PO₄)₂

Answer:

22.98 g, the mass of zinc (Zn) is needed to react with 23.1 g of phosphoric acid according to the given equation.

Explanation:

Given chemical reaction:

3 Zn + 2 H₃PO₄ = 3 H₂ + Zn₃(PO₄)₂

If the substance’ molecular weight is the number of grams required per mole, the number of moles expressed as a given quantity of substances shall correspond to the grams of that substance divided by the molecular weight. Hence,

$\text {number of moles}=\frac{\text {mass}}{\text {molar weight}}$

To find no. of moles of phosphoric acid:

Given:

mass of phosphoric acid = 23.1 g

molar weight of of phosphoric acid = 97.994 = 98 g/mole

Therefore,

no. of moles of phosphoric acid $=\frac{23.1}{98}=0.2357 \text { moles }$

Look into the given chemical reaction and divide as the following:

If 2 moles of H₃PO₄ reacts with 3 moles of Zn then 0.2357 moles of H₃PO₄ reacts with X moles of Zn. Then,

$\text { X moles of } \mathrm{Zn}=\frac{(0.2357 \times 3)}{2}=\frac{0.707}{2}=0.3535 \text { moles of } \mathrm{Zn}$

Now, calculate mass of zinc as follows, we know

molar mass of zinc is 65 g/mol

$mass\ of\ zinc = number\ of\ moles \times molar\ weight =0.3535 \times 65$

Mass of zinc = 22.98 g

7 0

3 years ago