The many electron diamonds around the central carbon are 1689
Answer: ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
of 0.056 M HF solution is 
Explanation:
cM 0 0
So dissociation constant will be:
Give c= 0.056 M and 
= ?
Putting in the values we get:
![[H^+]=c\times \alpha](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dc%5Ctimes%20%5Calpha)
![[H^+]=0.056\times 0.0016=8.96\times 10^{-5}](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.056%5Ctimes%200.0016%3D8.96%5Ctimes%2010%5E%7B-5%7D)
Thus of 0.056 M HF solution is
Answer:
The amount of Chlorodecane in the unknown is 0.105nmols
Explanation:
a) Since the GC is in an isothermal state, Chlorohexane C6H13Cl (1.69 nmols) because of its lower boiling point will elute first and Chlorodecane C12H21Cl will elute second.
The area of the first peak corresponding to Chlorohexane is 32434 units.
The area of the second peak corresponding to chlorodecane is 2022 units.
Since the response factor of the compound is not given in question and considering the response factor is same for both the compounds, the answer will be as follow:
1.69 nmols of Chlorohexane gives 32434 units
How much of chlorodecane gives 2022 units
By cross multiplication;
Moles of Chlorodecane = 2022*1.69/32434
=0.105nmols
Answer:
63.6%
Explanation:
The given compound is:
N₂O;
The problem here is to find the percent composition of nitrogen in the compound.
First find the molar mass of the compound:
Molar mass of N₂O = 2(14) + 16 = 44g/mol
So;
Percentage composition of Nitrogen = 
x 100 = 63.6%
Acetic Acid has two C atoms, four H atoms, and two O atoms, so the molecular formula is C2H4O2.
