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2 years ago

How many moles of H20 are required to react completely with 7.30 moles of NO2?

Chemistry

1 answer:

Paraphin [41]2 years ago

5 0

Answer:

2.43 moles of water are require.

Explanation:

Number of moles of water required = ?

Number of moles of NO₂ available = 7.30 mol

Solution:

Chemical equation:

3NO₂ + H₂O → NO + 2HNO₃

now we will compare the moles of NO₂ with H₂O.

NO₂ : H₂O

3 : 1

7.30 : 1/3×7.30 = 2.43 mol

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What is the mass of 3.04×10^-4 mol of baking soda, NaHCO3?

Zigmanuir [339]

Answer:

0.025536g

Explanation:

no. of mole = mass/Mr

mass = Mr × no. of mole

= [23 + 1 + 12 + 3(16)] × 3.04×10^-4

= 0.025536g

= 0.0255g (3 significant figures)

8 0

3 years ago

A sample of neon gas occupies a volume of 752ml at 25k. What volume will the gas occupy at 80k if the pressure remains constant

Anettt [7]

Answer:

The gas occupy 2406.4 mL at 80 K.

Explanation:

Given data:

Initial volume of gas = 752 mL

Initial temperature = 25 K

Final temperature = 80 K

Final volume = ?

Solution:

The given problem is solved by using charle's law.

V₁/T₁ = V₂/T₂

V₂ = V₁. T₂ /T₁

V₂ = 752 mL × 80 k / 25 K

V₂ = 60160 mL. k/25 K

V₂ = 2406.4 mL

7 0

2 years ago

Acetylene gas, C2H2, can be produced by the reaction of calcium carbide and water. CaC2(s) + 2H2O(l) --> C2H2(g) + Ca(OH)2(aq

nekit [7.7K]

Answer:

1.0 L

Explanation:

Given that:-

Mass of $CaC_2$ = $2.54\ g$

Molar mass of $CaC_2$ = 64.099 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{2.54\ g}{64.099\ g/mol}$

$Moles_{CaC_2}= 0.0396\ mol$

According to the given reaction:-

$CaC_2_{(s)} + 2H_2O_{(l)}\rightarrow C_2H_2_{(g)} + Ca(OH)_2_{(aq)}$

1 mole of $CaC_2$ on reaction forms 1 mole of $C_2H_2$

0.0396 mole of $CaC_2$ on reaction forms 0.0396 mole of $C_2H_2$

Moles of $C_2H_2$ = 0.0396 moles

Considering ideal gas equation as:-

$PV=nRT$

where,

P = pressure of the gas = 742 mmHg

V = Volume of the gas = ?

T = Temperature of the gas = $26^oC=[26+273]K=299K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles = 0.0396 moles

Putting values in above equation, we get:

$742mmHg\times V=0.0396 mole\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 299K\\\\V=\frac{0.0396\times 62.3637\times 299}{742}\ L=1.0\ L$

<u>1.0 L of acetylene can be produced from 2.54 g $CaC_2$ .</u>

4 0

2 years ago

PLEASE HURRY I NEED THE ANSWER TODAY

ludmilkaskok [199]

Answer:

A or B

Explanation:

6 0

3 years ago

Read 2 more answers

How many grams of C3H8

Tresset [83]

Answer:

91.28 g

Explanation:

7 0

2 years ago