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2 years ago

When does the transfer of thermal energy end?

Physics

1 answer:

Dahasolnce [82]2 years ago

6 0

Answer:

I think when the object transferring the thermal energy reaches the same temp as the object absorbing it

Explanation:

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A plane is flying east when it drops some supplies to a designated target below. The supplies land after falling for 10 seconds.

Ivanshal [37]

Part 1)

here we know that supply took 10 s to reach the ground

so here we will have

$y = \frac{1}{2}gt^2$

$y = \frac{1}{2}\times 9.8 \times 10^2$

$y = \frac{1}{2}\times 9.8 \times 100$

$y = 490 m$

Part 2)

Here all the supply covered horizontal distance of 650 m in 10 s interval of time

so here we can say

$speed = \frac{distance}{time}$

$v = \frac{650}{10}$

$v = 65 m/s$

4 0

3 years ago

A 35.8 kg box initially at rest is pushed 2.38 m along a rough, horizontal floor with a constant applied horizontal force of 108

tiny-mole [99]

Answer:

The work done by the applied force is 259.22 J.

Explanation:

The work done by the applied force is given by:

$W = F*d$

Where:

F: is the applied horizontal force = 108.915 N

d: is the distance = 2.38 m

Hence, the work is:

$W = F*d = 108.915 N*2.38 m = 259.22 J$

Therefore, the work done by the applied force is 259.22 J.

I hope it helps you!

6 0

3 years ago

M (b) Calculate the speed of an electron that is accelerated through the same electric potential difference.

MaRussiya [10]

The speed of a electron that is accelerated from rest through an electric potential difference of 120 V is $6.49\times10^6m/s$

<h3>How to calculate the speed of the electron?</h3>

We know, that the energy of the system is always conserved.

Using the Law of Conservation of energy,

$\triangle K+\triangle$ U=0

Here, K is the kinetic energy and U is the potential energy.

Now, substituting the formula of U and K, we get:

$(\frac{1}{2} mv^2)+(-q\triangle V)$ =0------(1)

Here,

m is the mass of the electron

v is the speed of the electron

q is the charge on the electron

V is the potential difference

Let $v_f$ and $v_i$ represent the final and initial speed.

Here, $v_i$ =0

Solving for $v_f$ , we get:

$v_f=\sqrt{\frac{-2q\triangle V}{m} }$

$=\sqrt{\frac{2\times1.602\times10^{-19}\times 120}{9.109\times10^{-31}} }$

=6.49 $\times10^6$ m/s

To learn more about the conservation of energy, refer to:

brainly.com/question/2137260

#SPJ4

4 0

1 year ago

What is the difference between convex and concave mirrors and lens?

Sidana [21]

Concave makes things smaller and convex makes things bigger

5 0

2 years ago

interval (from lowering the body to his feet taking off) lasts for 0.3 s and the mass of the player is 90 kg. Ignore air resista

steposvetlana [31]

Answer:

The force applied to the surface is 9 kilo Newton.

Explanation:

While jumping on the surface the player applies the force that is equal to its weight on the surface.

The mass of the player is given as 90 kg.

Force applied by the player = weight of the player

Force applied by the player = m × g

Where m is the mass of the player and g is acceleration due to gravity

Force applied by the player = 90 × 9.8

Force applied by the player = 882 Newton

Expressing your answer to one significant figure, we get

Force applied by the player =0. 9 kilo Newton

The force applied to the surface is 0.9 kilo Newton.

8 0

3 years ago

When does the transfer of thermal energy end?​

When does the transfer of thermal energy end?