Answer:
The answer to your question is: T2 = 235.44 °K
Explanation:
Data
V1 = 3.15 L V2 = 2.78 L
P1 = 2.40 atm P2 = 1.97 atm
T1 = 325°K T2 = ?
Formula
Process
T2 = (P2V2T1) / (P1V1)
T2 = (1.97x 2.78x 325) / (2.40 x 3.15)
T2 = 1779.895 / 7.56
T2 = 235.44 °K
Answer : The work done is,
Explanation :
The given balanced chemical reaction is:
When 4 moles of react with 12 moles of
then it gives 8 moles of
First we have to calculate the change in moles of gas.
Moles on reactant side = Moles of + Moles of
Moles on reactant side = 4 + 12 = 16 moles
Moles on product side = Moles of
Moles on reactant side = 8 moles
Change in moles of gas = 16 - 8 = 8 moles
Now we have to calculate the change in volume of gas.
Using ideal gas equation:
where,
P = Pressure of gas = 1.0 atm
V = Volume of gas = ?
n = number of moles of gas = 8 mole
R = Gas constant =
T = Temperature of gas =
Putting values in above equation, we get:
As the number of moles of gas decreased. So, the volume also deceased. Thus, the volume of gas will be, -195.7 L
Now we have to calculate the work done.
Formula used :
where,
w = work done
p = pressure of the gas = 1.0 atm
= change in volume = -195.7 L
Now put all the given values in the above formula, we get:
conversion used : (1 L.atm = 101.3 J)
Thus, the work done is,