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mash [69]
3 years ago
5

Do you believe that global warming is happening? Tell why or why not. If you believe global warming is happening, what can we do

to slow it down?
Physics
1 answer:
adoni [48]3 years ago
7 0

Answer:

Yes I do believe global warming is happening, mainly because there is a plethora of data and research from scientists to support the claim. The effects of global warming around us are clearly observed as well, such as the rise in acidity in the oceans. Another example is in the Artic, where a natural occurence takes place. Ice freezes and cold salty water takes its place, and because of it's high density it sinks and sweeps across the ocean floor. That cold water is then replaced by warmer water, and this is called the global ocean conveyor belt. As seen through the example with the Artic, ocean temperature plays a key role in the conveyor belt. Climate change is fueled through human activities, which could harm the system. If one part of the conveyor belt were to break down, such as the one in the Artic,  nutrients will not be distributed to start the food chain. Organisms such as phytoplankton need those nutrients to thrive. If phytoplankton are endangered, all life in the oceans is endangered. So as we can see, global warming is extremely harmful to the environment and it's effects are observed around us.

To slow global warming down we should consume less meat, and go to vegan or vegetarian diets. Your carbon footprint is halved by consuming less meat and eating a more vegan or vegetarian diet. Another thing is that we as a society should stop using so much plastic. It takes more than a century to degrade, most landfills are composed of it. Microplastics also get into our oceans, and our fish end up consuming them.

Explanation:

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A 0.71 W point source emits sound waves isotropically. Assuming that the energy of the waves is conserved, find the intensity (a
sveticcg [70]

Answer:

(a) 2.88×10⁻² W/m²

(b) 8.36×10⁻³ W/m²

Explanation:

The intensity of sound from an isotropic point source, with distance L is given as

I = P/(4πL²) .................................... Equation 1

Where I = intensity of sound, P = Power from the source, L = length, π = pie.

(a)

1.4 m from the source.

I = P/(4πL²)

Given: P = 0.71 W, L = 1.4 m, π = 3.14.

Substitute into equation 1

I = 0.71/(4×3.14×1.4²)

I = 0.71/24.6176

I = 0.0288 W/m².

I = 2.88×10⁻² W/m²

(b) 2.6 m from the source.

Given: P = 0.71 W, L = 2.6 m, π = 3.14

Substitute into equation 1

I = 0.71/(4×3.14×2.6²)

I = 0.71/84.9056

I = 0.00836 W/m²

I = 8.36×10⁻³ W/m²

5 0
3 years ago
A 75-hp compressor in a facility that operates at full load for 2500 h a year is powered by an electric motor that has an effici
stealth61 [152]

Answer:

C = 16544.35\, USD

Explanation:

The annual electricity cost is:

C = (\frac{1}{0.93} )\cdot(75\, h.p.)\cdot(0.746\, kW)\cdot(2500\,h)\cdot(\frac{3600\,s}{1\,h} )\cdot(\frac{1\,kWh}{3600\,kJ} )\cdot (0.11\,\frac{USD}{kWh} )

C = 16544.35\, USD

3 0
3 years ago
A red laser beam goes from crown glass with refraction index n=1.3 to air (n=1) with an incident angle of 0.23 radians. What is
Klio2033 [76]

Answer:

   θ = 10.28º

Explanation:

To find the angle of refraction use the equation of refraction

        n₁ sin θ₁ = n₂ sin θ₂

where index 1 is for incident light and index 2 is for refracted light.

         sin θ₂ = n₁ / n₂ sin θ

let's calculate

         sin = 1 / 1.3 sin 0.23

         sin = 0.175

        θ= 0.17528 rad

let's reduce to degrees

       θ = 0.17528 rad (180ª / pi rad)

       θ = 10.28º

6 0
3 years ago
In terms of newton first law of motion why is it important to wear a seat belt
lilavasa [31]

Answer:

Seatbelts stop you

Explanation:

Any passengers in the car will also be decelerated to rest if they are strapped to the car by seat belts.

6 0
3 years ago
Joseph studied whether different materials can block certain electromagnetic waves by testing television reception in different
gizmo_the_mogwai [7]
Using the same antenna. Now he doesn't know if it was the antenna that caused the change in reception. so he wasn't only measuring the reception in his house he was measuring it based on different antennas
7 0
3 years ago
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