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2 years ago

11

The blood pressure of aperson is 140/100 mm of Hg, what does it mean?

1 answer:

KonstantinChe [14]2 years ago

3 0

Answer:

If the blood pressure of a person is more than 120/80 mm of Hg, then it is especially called as high blood pressure.

Explanation:

But regarding answer to this question, The blood pressure of a

person is 140/100 mm of Hg means that the systolic blood pressure of a person is 140 mm of Hg and diastolic blood pressure of a person is 100 mm of Hg.

I hope this answer will help you

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Given that water at standard pressure freezes at 0∘c, which corresponds to 32∘f, and that it boils at 100∘c, which corresponds t

Zolol [24]

The temperature difference of 1 K is equivalent to the temperature difference of 1 °C. Therefore, we find the relationship between the change in °F and °C.
A change of 212 - 32 °F is the same as a change of 100 - 0 °C. Thus:
(212 - 32) °F = (100 - 0) °C
1 °C = 1.8 °F
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3 years ago

Which of the the following distance vs time graphs represents an object the is moving at constant non zero velocity

mario62 [17]

A graph with a horizontal line

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3 years ago

A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 6.8 m. The

Ber [7]

Answer:

1. $v=14.2259\ m.s^{-1}$

2. $F_T=25.8924\ N$

3. $\lambda=29.6373\ m$

Explanation:

Given:

mass of slinky, $m=0.87\ kg$

length of slinky, $L=6.8\ m$

amplitude of wave pulse, $A=0.23\ m$

time taken by the wave pulse to travel down the length, $t=0.478\ s$

frequency of wave pulse, $f=0.48\ Hz=0.48\ s^{-1}$

1.

$\rm Speed\ of\ wave\ pulse=Length\ of\ slinky\div time\ taken\ by\ the\ wave\ to\ travel$

$v=\frac{6.8}{0.478}$

$v=14.2259\ m.s^{-1}$

2.

<em>Now, we find the linear mass density of the slinky.</em>

$\mu=\frac{m}{L}$

$\mu=\frac{0.87}{6.8}\ kg.m^{-1}$

We have the relation involving the tension force as:

$v=\sqrt{\frac{F_T}{\mu} }$

$14.2259=\sqrt{\frac{F_T}{\frac{0.87}{6.8}} }$

$202.3774=F_T\times \frac{6.8}{0.87}$

$F_T=25.8924\ N$

3.

We have the relation for wavelength as:

$\lambda=\frac{v}{f}$

$\lambda=\frac{14.2259}{0.48}$

$\lambda=29.6373\ m$

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2 years ago

True [87]

Answer:

$\Delta T=3.615^{\circ}C$ is the drop in the water temperature.

Explanation:

Given:

mass of ice, $m_i=14.7\ g=0.0147\ kg$

mass of water, $m_w=324\ g=0.324\ kg$

Assuming the initial temperature of the ice to be 0° C.

<u>Apply the conservation of energy:</u>

Heat absorbed by the ice for melting is equal to the heat lost from water to melt ice.

<u>Now from the heat equation:</u>

$Q_i=Q_w$

$m_i.L=m_w.c_w.\Delta T$ ......................(1)

where:

$L=$ latent heat of fusion of ice $=333.55\ J.g^{-1}$

$c_w=$ specific heat of water $=4.186\ J.g^{-1}.^{\circ}C^{-1}$

$\Delta T=$ change in temperature

Putting values in eq. (1):

$14.7 \times 333.55=324\times 4.186\times \Delta T$

$\Delta T=3.615^{\circ}C$ is the drop in the water temperature.

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2 years ago

If you were to double the separation between two slits, by what factor would the number of interference fringes within the centr

NemiM [27]

Answer The fringes become closer together as the slits are moved farther apart.

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3 years ago