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Tema [17]
3 years ago
13

Can you go around a curve with zero acceleration? Explain​

Physics
1 answer:
Serjik [45]3 years ago
6 0
“Yes, it is impossible to go around the curved path with zero acceleration. Acceleration is change in velocity. And velocity( speed+ direction) changes at every point in a curved path because there is change in direction at every point.”
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What type of terms the rest and motion are?​
andriy [413]

Answer:

Rest and Motion are relative terms.

5 0
3 years ago
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Displacement is which of the following types of quantities?A. vectorB. scalarC. magnitudeD. dimensional
agasfer [191]

Answer: A. vector

Explanation:

Movement is the change of position of a body at a certain time. The body that experiences this change of position is called mobile.

In this sense, the <u>displacement</u> is the distance in a straight line between the initial and final position of this mobile, which differentiates it from <u>the trajectory, </u> which is the <u>path followed by the body in its movement and a scalar magnitude.</u>

Hence, the displacement is a vector.

6 0
3 years ago
A particle with charge q = +5e and mass m = 8.2×10-26 kg is injected horizontally with speed 1.1×106 m/s into the region between
loris [4]

Answer:

d = 1.27m

Explanation:

Given m = 8.2×10-26kg, v = 1.1×10⁶m/s, q = +5e = 5×1.6×10‐¹⁹ C.

E = 49kN/C = 49000N/C

The displacement is given by

d = 1/2× mv²/qE = 1/2 × 8.2×10-²⁶ × (1.1×10⁶)²/(5×1.6×10-¹⁹ ×49000) = 1.27m

3 0
3 years ago
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A 0.026 kg bullet is fired straight up at a falling wooden block that has a mass of 5.0 kg. The bullet has a speed of 750 m/s wh
Law Incorporation [45]

Answer:

0.198 s

Explanation:

Consider the motion of the block  before collision

v_{o} = initial velocity of block as it is dropped = 0 m/s

a = acceleration = - g

t = time of travel

v_{f} = final velocity of block before collision

Using the kinematics equation

v_{f} = v_{o} + at \\v_{f} = 0 + (-g)t\\v_{f} = - gt

m = mass of the bullet = 0.026 kg

v_{b} = velocity of block just before collision = 750 m/s

M = mass of the block = 5 kg

V = final velocity of bullet block after collision = gt

Using conservation of momentum

m v_{b} + Mv_{f} = (m + M) V\\(0.026) (750) + (5) (- gt) = (0.026 + 5) (gt)\\19.5 - 49 t = 49.2548 t\\t = 0.198 s

8 0
3 years ago
If I start with 32g of Iodine-131, how much will I have after 24 days?
mihalych1998 [28]

  • Iodine-131. Iodine-131 decays by beta emission and has a half-life of 8.04 days. The principal gamma emission of 364 keV is considerably higher than the ideal for imaging with gamma cameras.

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