Answer:
r = 20.22 m
Explanation:
Given that,
Charge,
Electric field,
We need to find the distance. We know that, the electric field a distance r is as follows :
So, the required distance is 20.22 m.
The coefficient of static friction is 0.357 and the coefficient of kinetic friction is 0.265.
Explanation:
Coefficient of static friction is defined as the proportionality constant for the frictional force between the crate and floor for starting the motion of crate and normal force acting on the crate. As the normal force of the crate is equal to the influence of acceleration due to gravity acting on the mass of the crate, the frictional force for static friction coefficient will be the force applied to move the crate.
Thus,
Since, the static friction force is 70 N, the normal force is equal to
So normal force is 196 N and static force is 70 N, and the ratio of static friction force to the normal force will give the coefficient of static friction.
Similarly, the coefficient of kinetic friction can be determined from the ratio of kinetic friction force to normal force. Here the kinetic friction force will be equal to the force applied on the crate to keep it moving.
Thus, the coefficient of static friction is 0.357 and the coefficient of kinetic friction is 0.265.
The cell wall does not transfer genetic materials
Answer:
2 cm.
Explanation:
Please see attached photo for diagram.
In the attached photo, y is the distance from the pivot to which the 25 g is placed.
The value of y can be obtained as follow:
Clockwise moment = 5 × 10
Anticlock wise moment = y × 25
Anticlock wise moment = Clockwise moment
y × 25 = 5 × 10
y × 25 = 50
Divide both side by 25
y = 50/25
y = 2 cm
Thus, the distance is 2 cm
Force causes an object to move in the same direction that the force is applied. Friction reduces efficiency<span> when two surfaces slide past each other, also </span>friction<span> resists their motion, and in </span>machines<span>, some input work is always used to overcome </span>friction<span>.
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