I cant belive im doing this- i will mark brainliest if this gets answered- mostly correct.

Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th

Mariulka [41]

Answer:

a) 0.0288 grams

b) $2.6*10^{-10} J/kg$

Explanation:

Given that:

A typical human body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

a)

Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.

However, the amount of potassium that is present in such person is :

0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

b)

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = $\frac{energy \ absorbed }{mass \ of \ the \ body}$

= $\frac{1.10*10^6*1.6*10^{-14}}{80}$

= $2.2*10^{-10} \ J/kg$

Effective dose (Sv) = RBE × Dose in Gy

Effective dose (Sv) = $1.2 *2.2*10^{-10} \ J/kg$

Effective dose (Sv) = $2.6*10^{-10} J/kg$

5 0

4 years ago

I want the answer pls

storchak [24]

Answer:

Percentage error = 2.63%

Explanation:

We are given the following

Original volume = 15.20mL

Student measurement = 14.8mL

Error = 15.20-14.80

Error = 0.40mL

percentage = Error/Original volume * 100

Percentage error = 0.4/15.20 * 100

Percentage error = 40/15.20

Percentage error = 2.63%

3 0

3 years ago

A block of mass m, initially held at rest on a frictionless ramp a vertical distance H above the floor, slides down the ramp and

-Dominant- [34]

Answer:

Explanation:

Check attachment for solution

4 0

3 years ago

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Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 2.1×109 electrons from one disk to the

Bad White [126]

Answer:

$d = 0.018 m$

Explanation:

Charge on the plates of the capacitor due to transfer of electrons is given as

$Q = Ne$

here we know that

$N = 2.1 \times 10^9$

so we have

$Q = (2.1 \times 10^9)(1.6 \times 10^{-19})$

$Q = 3.36 \times 10^{-10} C$

now we have electric field between the plates is given as

$E = \frac{Q}{A\epsilon_0}$

here we have

$1.5 \times 10^5 = \frac{3.36 \times 10^{-10}}{A(8.85 \times 10^{-12})}$

$A = 2.53 \times 10^{-4} m^2$

now we have

$A = \frac{\pi d^2}{4}$

$2.53 \times 10^{-4} = \frac{\pi d^2}{4}$

$d = 0.018 m$

3 0

3 years ago

What is the frequency of motion of a 0.50 m long pendulum?

IgorC [24]

Complicated 2-step process.

1. Write down the formula for "frequency of a pendulum" from your textbook. 

f = (1/2pi) * sqrt(g/L) 

2. Plug in g and L.

I hope this can help!

3 0

3 years ago

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