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Eddi Din [679]
3 years ago
10

What is the attractive force between all matter in the universe?

Physics
2 answers:
kvv77 [185]3 years ago
4 0
The attractive force between all matter in the universe is gravity.
Sholpan [36]3 years ago
3 0

Answer:

Gravitational force

Explanation:

As we know that there are four fundamental force in nature

1) Gravitational Force : It is always attraction type of force which exist between two objects of different masses.

2) Electromagnetic force : It may be of attraction or repulsion type of force depends on the charge or pole of the given object.

3) Weak or strong nuclear force : This force depends on the distance between the particles. For a certain range of distance this force is of attraction type force while for other range it is repulsion type of force.

So here from above description we know that only gravitation force is the attraction type of force for all conditions so here correct answer will be

Gravitational Force

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vovikov84 [41]
Based on Newton's second law of motion, the net force applied to an object is equal to the product of the mass of the object and the acceleration it experiences. That is,
  
          F = ma

If we are to assume that the net force is constant and that the mass is increased, the acceleration should therefore decrease in order to make constant the value at the right-hand side of the equation. 
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3 years ago
A person is attracted toward the centerof the earth by a 500 n gravitational force. the force with which the earth is attracted
nignag [31]
500 N  is the answer, you just tell that the moon is attracted towards the person because of the Earth's huge mass. 
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3 years ago
a tire with inner volume of 0.0250m^3 is filled with air at a gauge pressure of 36.0 psi. If the tire valve is opened to the atm
enyata [817]

Answer: Escaped volume = 0.0612m^3

Explanation:

According to Boyle's law

P1V1 = P2V2

P1 = initial pressure in the tire = 36.0psi + 14.696psi = 50.696psi (guage + atmospheric pressure)

P2 = atmospheric pressure= 14.696psi

V1 = volume of tire =0.025m^3

V2 = escaped volume + V1 ( since air still remain in the tire)

V2 = P1V1/P2

V2 = 50.696×0.025/14.696

V2 = 0.0862m^3

Escaped volume = 0.0862 - 0.025 = 0.0612m^3

5 0
3 years ago
un resorte de 10cm de longitud recibe una magnitud de fuerza que lo estira hasta medir 15cm ¿cual es la magnitud de la tension u
Ber [7]

Answer: 0.5

Explanation:

The modulus of elasticity (called <em>"alargamiento unitario"</em> in spanish) \epsilon of a spring is given by the following formula:

\epsilon=\frac{\Delta L}{L}

Where:

L=10 cm  is the original length of the spring

\Delta L=L_{f}-L  is the elongation of the spring, being L_{f}=15 cm the length of the spring after a force is applied to it.

\epsilon=\frac{L_{f}-L}{L}=\frac{15 cm - 10 cm}{10 cm}

Then:

\epsilon=0.5

8 0
4 years ago
How is power defined?
erastova [34]

d. the rate at which work is accomplished

6 0
4 years ago
Read 2 more answers
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