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Eddi Din [679]
3 years ago
10

What is the attractive force between all matter in the universe?

Physics
2 answers:
kvv77 [185]3 years ago
4 0
The attractive force between all matter in the universe is gravity.
Sholpan [36]3 years ago
3 0

Answer:

Gravitational force

Explanation:

As we know that there are four fundamental force in nature

1) Gravitational Force : It is always attraction type of force which exist between two objects of different masses.

2) Electromagnetic force : It may be of attraction or repulsion type of force depends on the charge or pole of the given object.

3) Weak or strong nuclear force : This force depends on the distance between the particles. For a certain range of distance this force is of attraction type force while for other range it is repulsion type of force.

So here from above description we know that only gravitation force is the attraction type of force for all conditions so here correct answer will be

Gravitational Force

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Sunspots appear dark because they are cooler than the surrounding solar surface. True or false
DiKsa [7]

Answer:

False, Sunspots appear dark (in visible light) due to their low temperature(cooler) than rest of the sun

Explanation:

Sunspots appear dark because they are much cooler( have low temperature than the rest of the surface contained by Sun. As they appear dark, but still they have very temperature that's why so hot. Sunspots have temperatures ranges  3,500 Celsius (3773 kelvin) and the surrounding surface of the sun has a temperature much higher of about 5,500 Celsius(5773 Kelvin). Even if we see a sunspot alone in space,  it will glow so brightly.

Learn more about sunspots :

brainly.com/question/27774496

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6 0
2 years ago
We know that every object exerts an attraction on every other object and the heavier the object ___ the attraction.
hichkok12 [17]
I don't know what the exact word is, but I do know that the bigger an objects mass is the more it will attract other objects toward it, mainly smaller objects with less mass. it might be gravity or something around those lines....is it a multiple choice question? 
6 0
3 years ago
PLEASE HELP!
Kobotan [32]

Answer:

No

Explanation:

Cause a monster truck don

3 0
2 years ago
To determine the muzzle velocity of a bullet fired from a rifle, you shoot the 2.47-g bullet into a 2.43-kg wooden block. The bl
Elza [17]

Answer:

The velocity of the bullet on leaving the gun's barrel is 236.36 m/s.

Explanation:

Given;

mass of the bullet, m₁ = 2.47 g = 0.00247 kg

mass of the wooden block, m₂ = 2.43 kg

initial velocity of the wooden block, u₂ = 0

height reached by the bullet-block system after collision = 0.295 cm = 0.00295 m

let the initial velocity of the bullet on leaving the gun's barrel = v₁

let final velocity of the bullet-wooden block system after collision = v₂

Apply the principle of conservation of linear momentum;

Total initial momentum = Total final momentum

m₁v₁ + m₂u₂ = v₂(m₁ + m₂)

0.00247v₁  + 2.43 x 0  =  v₂(2.43 + 0.00247)

0.00247v₁ = 2.4325v₂ -------(1)

The kinetic energy of the bullet-block system after collision;

K.E = ¹/₂(m₁ + m₂)v₂²

K.E = ¹/₂ (2.4325)v₂²

The potential energy of the bullet-block system after collision;

P.E = mgh

P.E = (2.4325)(9.8)(0.00295)

P.E = 0.07032

Apply the principle of conservation of mechanical energy;

K.E = P.E

¹/₂ (2.4325)v₂² = 0.07032

1.21625 v₂²  = 0.07032

v₂²  = 0.07032  / 1.21625

v₂² = 0.0578

v₂ = √0.0578

v₂ = 0.24 m/s

Substitute v₂ in equation (1), to obtain the initial velocity of the bullet;

0.00247v₁ = 2.4325v₂

0.00247v₁ = 2.4325 (0.24)

0.00247v₁ = 0.5838

v₁ = 0.5838 / 0.00247

v₁ = 236.36 m/s

Therefore, the velocity of the bullet on leaving the gun's barrel is 236.36 m/s.

5 0
3 years ago
A truck of mass 1800kg is moving with a speed 54km/h. When brakes are applied, it
EleoNora [17]

Force = 3200 N

Work done = 640, 000 Nm

Explanation:

We begin by calculating the deceleration of the truck, using the velocity and distance;

a = (v² – u²)/2s

whereby;

a = acceleration

v = initial velocity

u = initial velocity

s = distance

We begin by changing the speed from km/h into m/s;

54km/hr = 15m/s

Then acceleration;

a = (0² – 15²) / 2 * 200

a = -225 / 400

a = - 0.5625 m/ s²

To calculate force;

F = ma

Whereby;

F = force

M = mass (in kgs)

a = acceleration

F = 1800 / 0.5625

F = 3200 N

Work done = Force * displacement

Work done = 3200 * 200

= 640, 000 Nm

Learn More:

For more on force and work done check out;

brainly.com/question/8662583

brainly.com/question/1268612

brainly.com/question/11870590

brainly.com/question/9125094

#LearnWithBrainly

6 0
3 years ago
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