The pressure exerted by 0.400 moles of carbon dioxide in a 5.00 Liter container at 25 °C would be 1.9563 atm or 1486.788 mm Hg.
<h3>The ideal gas law</h3>
According to the ideal gas law, the product of the pressure and volume of a gas is a constant.
This can be mathematically expressed as:
pv = nRT
Where:
p = pressure of the gas
v = volume
n = number of moles
R = Rydberg constant (0.08206 L•atm•mol-1K)
T = temperature.
In this case:
p is what we are looking for.
v = 5.00 L
n = 0.400 moles
T = 25 + 273
= 298 K
Now, let's make p the subject of the formula of the equation.
p = nRT/v
= 0.400 x 0.08206 x 298/5
= 1.9563 atm
Recall that: 1 atm = 760 mm Hg
Thus:
1.9563 atm = 1.9563 x 760 mm Hg
= 1486.788 mm Hg
In other words, the pressure exerted by the gas in atm is 1.9563 atm and in mm HG is 1486.788 mm Hg.
More on the ideal gas law can be found here: brainly.com/question/28257995
#SPJ1
Answer:
gain or loses electrons.
Explanation:
Because the atom need to be balanced.
Group 1 atoms only have one. Group 2 has 2 valence electrons, and so on.
We can see that 2 moles of The no react with 1 mole of O2 using this equation. 4.8 L NO x 1 L O2 / 2 L NO = 2.4 L of O2 are needed at constant pressure and temperature.
What is an example of pressure?
One can see a simple illustration of pressure by using a knife against a few fruit. If you press the flat side of the knife against the fruit, the top won't be cut. The force is spread more than a wide area (low pressure).
What are different types of pressure?
The physical pressure exerted to an object is referred to as pressure. Per unit area, a parallel force is applied to the surface of the objects. F/A (Force per Area) is the basic formula for pressure.
To know more about pressure visit:
brainly.com/question/12971272
#SPJ4
Answer: The pH of phenol solution is 4.7
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydronium ion concentration.
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
Given : ![[H_3O^+]=1.8\times 10^{-5}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D1.8%5Ctimes%2010%5E%7B-5%7DM)
Putting in the values we get
![pH=-\log[1.8\times 10^{-5}M]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B1.8%5Ctimes%2010%5E%7B-5%7DM%5D)

Thus pH of phenol solution is 4.7